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Conservation of Energy

Energy transfer diagrams and conservation of energy

  • 3 things to know
  • Paper 1

Overview

What energy transfer and Sankey diagrams show, arrow widths and why outputs equal the input, diagrams for a torch and a hairdryer, the principle of conservation of energy, and why energy is wasted but never used up.

What you need to know

Answer each one before you reveal it.

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Key term

State the principle of conservation of energy, then use the principle to explain a braking car and the limit on a machine's output.

Key term

In a Sankey diagram, what does the width of each arrow represent?

Key term

In a Sankey diagram for an electric lamp, why is the input arrow wider than the arrow representing the light output?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What does an energy transfer diagram show about a change taking place in a system?

    Model answer

    It shows which stores the energy starts in, which stores it ends in, and how much is transferred along each pathway.

  2. 2

    In a Sankey diagram, what does the width of each arrow represent?

    Model answer

    The width of each arrow is proportional to the amount of energy transferred along that pathway.

  3. 3

    In a Sankey diagram for an electric lamp, why is the input arrow wider than the arrow representing the light output?

    Model answer

    The input includes both the useful light and the energy dissipated by heating, so it is wider than the light arrow alone.

  4. 4

    State what the total width of all the output arrows of a Sankey diagram must equal.

    Model answer

    It must equal the width of the input arrow, because energy is conserved.

  5. 5

    Describe in words the energy transfer diagram for a battery-powered torch.

    Model answer

    Energy is transferred from the chemical store of the battery to light, and to the thermal store of the surroundings.

  6. 6

    An energy transfer diagram for a hairdryer shows 1000 J supplied, 900 J transferred by heating and 40 J as sound. Calculate the energy transferred along the remaining pathway.

    Model answer

    1000 − 900 − 40 = 60 J is transferred along the remaining pathway.

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