Edexcel GCSE Combined Science Physics 1SC0
Key Concepts of Physics
Motion and Forces
Conservation of Energy
Waves
Light and the Electromagnetic Spectrum
Radioactivity
Energy – Forces Doing Work
Forces and Their Effects
Electricity and Circuits
Magnetism and the Motor Effect
Electromagnetic Induction
Particle Model
Radioactivity
Balancing nuclear equations
- 3 things to know
- Paper 5
Overview
Balancing mass number and charge in a nuclear equation, finding an unknown nucleus or particle, and how β⁻ particles and positrons are written.
What you need to know
Answer each one before you reveal it.
In the decay ²³⁸₉₂U → X + ⁴₂He, state the mass number and atomic number of nucleus X.
In the decay ⁹⁰₃₈Sr → X + ⁰₋₁e, state the mass number and atomic number of nucleus X.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What two quantities must balance on the two sides of a nuclear equation?
Model answer
The total mass number and the total charge.
- 2
In the decay ²³⁸₉₂U → X + ⁴₂He, state the mass number and atomic number of nucleus X.
Model answer
X has mass number 234 and atomic number 90.
- 3
In the decay ⁹⁰₃₈Sr → X + ⁰₋₁e, state the mass number and atomic number of nucleus X.
Model answer
X has mass number 90 and atomic number 39.
- 4
How is a β⁻ particle written in a nuclear equation?
Model answer
It is written as ⁰₋₁e, with a mass number of 0 and a charge of −1.
- 5
How is a positron written in a nuclear equation?
Model answer
It is written as ⁰₊₁e, with a mass number of 0 and a charge of +1.
- 6
In the decay ¹⁸₉F → ¹⁸₈O + X, what particle is X?
Model answer
X is a positron.
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