OCR GCSE Chemistry A J248
Chemical Reactions
Elements, Compounds and Mixtures
Global Challenges
Monitoring and Controlling Chemical Reactions
Particles
Predicting and Identifying Reactions
Chemical Reactions
Stoichiometry, and calculating reacting masses
- 3 things to know
- Paper 3
Overview
What stoichiometry shows, deducing an equation from reacting masses, limiting reactants and reactants in excess, and calculating masses of product or reactant from balanced equations for magnesium oxide, calcium oxide, hydrogen, water and sodium chloride.
What you need to know
Answer each one before you reveal it.
48 g of magnesium reacts exactly with 32 g of oxygen. Deduce the equation. Relative atomic masses: Mg 24, O 16.
2.3 g of sodium reacts exactly with 3.55 g of chlorine. Deduce the ratio and the equation. Relative atomic masses: Na 23, Cl 35.5.
Questions from this subtopic
Each one with the model answer underneath.
- 1
What does the stoichiometry of an equation tell you?
Model answer
The ratio in which the substances react and are formed, given by the large numbers in front of the formulae.
- 2
48 g of magnesium reacts exactly with 32 g of oxygen. Deduce the equation. Relative atomic masses: Mg 24, O 16.
Model answer
2 mol of magnesium reacts with 1 mol of oxygen molecules, giving 2Mg + O₂ → 2MgO.
- 3
2.3 g of sodium reacts exactly with 3.55 g of chlorine. Deduce the ratio and the equation. Relative atomic masses: Na 23, Cl 35.5.
Model answer
0.1 mol of sodium to 0.05 mol of chlorine molecules, a 2 to 1 ratio, giving 2Na + Cl₂ → 2NaCl.
- 4
What is a limiting reactant?
Model answer
The reactant that is used up first and so stops any more product from being made.
- 5
What is meant by saying a reactant is in excess?
Model answer
More of it is supplied than is needed, so some is left unreacted when the reaction stops.
- 6
Which reactant controls the amount of product that can be made, and why?
Model answer
The limiting reactant, because once it has run out no further product can form however much of the other remains.
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