OCR GCSE Chemistry A J248
Chemical Reactions
Elements, Compounds and Mixtures
Global Challenges
Monitoring and Controlling Chemical Reactions
Particles
Predicting and Identifying Reactions
Monitoring and Controlling Chemical Reactions
- 12 subtopics
- 36 things to know
- Paper 4
What Monitoring and Controlling Chemical Reactions covers
Monitoring and Controlling Chemical Reactions is examined in Chemistry A Paper 4. It covers concentration in mol/dm³ and titration; titration calculations and the mass of a solute; molar gas volume and the volumes of gases; theoretical mass and percentage yield; atom economy and choosing a reaction pathway; measuring the rate of a reaction and rate graphs; factors affecting rate and collision theory; surface area and rate; catalysts and how they work; reversible reactions and dynamic equilibrium; changing the conditions of an equilibrium; and activation energy and enzymes as catalysts.
Where it is assessed
Paper 4
Chemistry A Paper 4: 1 hour 45 minutes, 90 marks, 50% of the GCSE.
Check the OCR specification ↗The 12 subtopics
Each one has its own page.
- Concentration in mol/dm³, and titrationWhat concentration in mol/dm³ means and how it relates to moles and volume, converting cm³ to dm³, calculating concentrations and masses and converting from g/dm³, the effect of dilution, the pipette, burette, white tile and indicators used in a titration, what the end point is, reading a burette, rough titrations and concordant titres.Open →
- Titration calculations, and the mass of a soluteThe three steps from titration results to an unknown concentration, worked titration calculations including a 1:2 ratio, averaging concordant titres, converting mol/dm³ to g/dm³, and mass, volume and concentration calculations.Open →
- Molar gas volume and the volumes of gasesThe 24 dm³ molar gas volume at room temperature and pressure, why every gas occupies the same volume, converting between moles and volume, and calculating gas volumes from reacting masses and equations.Open →
- Theoretical mass and percentage yieldWhat a theoretical mass is and the three steps to calculate it, worked examples from calcium carbonate, magnesium, nitrogen and hydrogen, the limiting reactant, percentage yield calculations, and why yields fall short of 100%.Open →
- Atom economy, and choosing a reaction pathwayWhat atom economy is and how it is calculated, when it reaches 100%, why manufacturers want it high and how it differs from percentage yield, what happens to by-products, worked calculations for calcium oxide, iron, ammonia, hydrogen, oxygen and magnesium chloride, and choosing a reaction pathway by weighing atom economy, yield, rate, equilibrium position and useful by-products.Open →
- Measuring the rate of a reaction, and rate graphsWhat rate means, following a reaction with a gas syringe, a balance, a disappearing cross, a colorimeter or a pH probe, the units of rate, and reading the gradient of a rate graph.Open →
- Factors affecting rate, and collision theoryHow temperature, concentration, pressure and surface area affect rate, why concentration changes the speed but not the amount of product, the rough doubling for each 10 °C rise, how rate changes during a reaction, the two conditions for a successful collision, explaining each factor with collision theory and activation energy, reading rate ∝ 1/t, and planning, evaluating and improving the sodium thiosulfate investigation.Open →
- Surface area and rateHow breaking a solid up raises its surface area to volume ratio, why powders react faster, the cube calculations, the flour dust hazard, and comparing the graphs for powder and lumps.Open →
- Catalysts and how they workWhat a catalyst is, why its mass is unchanged and it sits above the arrow, why catalysts are specific and used in industry, and the catalysts for hydrogen peroxide, ammonia and sulfuric acid.Open →
- Reversible reactions and dynamic equilibriumWhat a reversible reaction is and its symbol, why the reverse of an exothermic reaction is endothermic, heating hydrated copper(II) sulfate and testing for water, heating ammonium chloride, the nitrogen and hydrogen that form ammonia, what dynamic equilibrium and a closed system are, what the position of equilibrium means, and how the forward and reverse rates change until equilibrium is reached.Open →
- Changing the conditions of an equilibriumLe Chatelier’s principle, and the effect on the position of equilibrium of changing concentration, removing a product, raising or lowering the temperature, and changing the pressure, with the compromise conditions for ammonia and sulfur trioxide.Open →
- Activation energy, and enzymes as catalystsHow a catalyst gives a pathway with a lower activation energy, reaction profiles for catalysed reactions, why lowering the activation energy speeds a reaction, calculating activation energies and energy changes from profiles, what enzymes are and why organisms need them, denaturing by heat and pH, enzyme specificity, uses in brewing and washing powders, and how enzymes compare with metal catalysts.Open →
What you need to know
Answer each one before you reveal it.
For the exothermic equilibrium 2SO₂ + O₂ ⇌ 2SO₃, why is a moderately high temperature used and what does raising the pressure do?
When is atom economy 100%, why do manufacturers prefer a high atom economy, and how does atom economy differ from percentage yield?
State the relationship between concentration, number of moles of solute and volume of solution.
State the three steps used to work out an unknown concentration from titration results.
Express the volume of one mole of gas at room temperature and pressure in cm³.
State the three steps used to calculate the theoretical mass of a product from a given mass of reactant.
Describe the effect of raising the temperature on the rate of a reaction.
Explain why a powdered solid reacts faster than the same mass of the solid in one large lump.
Explain why only a small mass of catalyst is needed to convert a very large mass of reactant.
What symbol is used in an equation to show that a reaction is reversible?
Describe how the reaction profile for a catalysed reaction differs from that of the same reaction without a catalyst.
How do you convert a volume measured in cm³ into dm³?
How do you calculate the number of moles in a solution from its concentration in mol/dm³ and its volume in cm³?
How do you calculate the number of moles of a gas from its volume in dm³ at room temperature and pressure?
If one reactant is present in excess, which reactant must the theoretical mass be calculated from?
Under what circumstances does a reaction have an atom economy of 100%?
In general terms, what two quantities can be followed over time to measure the rate of a reaction?
Describe the effect of increasing the concentration of a reactant in solution on the rate of a reaction.
Which particles of a solid reactant are able to take part in a reaction with a solution?
Describe how you could show experimentally that a substance added to a reaction acted as a catalyst.
How is anhydrous copper(II) sulfate used as a test for water?
State the principle used to predict how the position of an equilibrium responds to a change in conditions.
Explain why lowering the activation energy makes a reaction faster.
A solution contains 0.50 mol of solute in 250 cm³ of solution. Calculate its concentration in mol/dm³.
Why must the balanced equation be used in a titration calculation rather than assuming the moles are equal?
How do you calculate the volume of a gas at room temperature and pressure from the number of moles?
How is the percentage yield of a reaction calculated?
Give two reasons why a manufacturer prefers a process with a high atom economy.
Suggest how a balance can be used to measure the rate of a reaction that releases a gas, and explain why the mass changes.
Describe the effect of increasing the pressure on a reaction between gases.
A cube of solid has sides of 3 cm. Calculate its surface area, its volume and its surface area to volume ratio.
Name a metal used as the catalyst in a car's catalytic converter.
Name the two gases that combine reversibly to make ammonia.
Predict the effect of increasing the concentration of a reactant on the position of an equilibrium.
A reaction profile shows the reactants at 100 kJ/mol, the peak at 180 kJ/mol and the products at 40 kJ/mol. Calculate the activation energy and the overall energy change.
Take Monitoring and Controlling Chemical Reactions further
The same content, four other ways.
Commonly confused
Pairs that lose marks when they are blurred together.
Percentage yield vs Atom economy
Percentage yield: actual mass of product divided by the theoretical mass, times 100. Atom economy: proportion of the reactant mass that ends up as the desired product.
Dynamic equilibrium vs Reversible reaction
Dynamic equilibrium: closed-system state where forward and reverse rates are equal. Reversible reaction: products can react together to re-form the original reactants.
Concordant titres vs Rough titration
Concordant titres: repeat readings that agree within 0.10 cm³ of each other. Rough titration: first quick run to locate the end point.
Questions from this topic
Each one with the model answer underneath.
- 1
What does the concentration of a solution measured in mol/dm³ tell you?
Model answer
It tells you how many moles of solute are dissolved in each cubic decimetre of solution.
- 2
State the relationship between concentration, number of moles of solute and volume of solution.
Model answer
Concentration in mol/dm³ equals the number of moles of solute divided by the volume of the solution in dm³.
- 3
How do you convert a volume measured in cm³ into dm³?
Model answer
Divide the volume in cm³ by 1000.
- 4
A solution contains 0.50 mol of solute in 250 cm³ of solution. Calculate its concentration in mol/dm³.
Model answer
250 cm³ is 0.250 dm³, so the concentration is 0.50 ÷ 0.250 = 2.0 mol/dm³, given to 2 significant figures.
- 5
4.0 g of sodium hydroxide, relative formula mass 40, is dissolved to make 500 cm³ of solution. Calculate the concentration in mol/dm³.
Model answer
4.0 ÷ 40 = 0.10 mol of solute in 0.500 dm³, so the concentration is 0.10 ÷ 0.500 = 0.20 mol/dm³, given to 2 significant figures.
- 6
Calculate the mass of sodium hydroxide, relative formula mass 40, in 100 cm³ of a solution of concentration 2.00 mol/dm³.
Model answer
2.00 × 0.100 = 0.200 mol, and 0.200 × 40 = 8.00 g, given to 3 significant figures.
What is inside Levo
Six ways to work the same material.
Monitoring and Controlling Chemical Reactions revision questions
- What does Monitoring and Controlling Chemical Reactions cover in OCR GCSE Chemistry A?
- 12 subtopics: concentration in mol/dm³, and titration, titration calculations, and the mass of a solute, molar gas volume and the volumes of gases, theoretical mass and percentage yield, atom economy, and choosing a reaction pathway, measuring the rate of a reaction, and rate graphs, factors affecting rate, and collision theory, surface area and rate, catalysts and how they work, reversible reactions and dynamic equilibrium, changing the conditions of an equilibrium and activation energy, and enzymes as catalysts. Each one has its own page with questions and model answers.
- How is Monitoring and Controlling Chemical Reactions organised?
- By the OCR J248 specification, subtopic by subtopic, so it matches the order you are taught it in.
Every question in Monitoring and Controlling Chemical Reactions, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.