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Monitoring and Controlling Chemical Reactions

Theoretical mass and percentage yield

  • 3 things to know
  • Paper 4

Overview

What a theoretical mass is and the three steps to calculate it, worked examples from calcium carbonate, magnesium, nitrogen and hydrogen, the limiting reactant, percentage yield calculations, and why yields fall short of 100%.

What you need to know

Answer each one before you reveal it.

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Process

State the three steps used to calculate the theoretical mass of a product from a given mass of reactant.

Key term

If one reactant is present in excess, which reactant must the theoretical mass be calculated from?

Key term

How is the percentage yield of a reaction calculated?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is meant by the theoretical mass of a product?

    Model answer

    It is the maximum mass of product that could be made if all the reactant were converted and none of the product were lost.

  2. 2

    State the three steps used to calculate the theoretical mass of a product from a given mass of reactant.

    Model answer

    Convert the mass of reactant to moles, use the balanced equation to find the moles of product, then multiply by the relative formula mass of the product.

  3. 3

    Calcium carbonate, relative formula mass 100, decomposes to calcium oxide, relative formula mass 56, in a 1:1 ratio. Calculate the theoretical mass of calcium oxide from 50.0 g of calcium carbonate.

    Model answer

    50.0 ÷ 100 = 0.500 mol, giving 0.500 mol of calcium oxide, so 0.500 × 56 = 28.0 g, given to 3 significant figures.

  4. 4

    Magnesium, relative atomic mass 24, burns to magnesium oxide, relative formula mass 40, one mole of metal giving one mole of oxide. Calculate the theoretical mass of oxide from 4.8 g of magnesium.

    Model answer

    4.8 ÷ 24 = 0.20 mol, giving 0.20 mol of magnesium oxide, so 0.20 × 40 = 8.0 g, given to 2 significant figures.

  5. 5

    One mole of nitrogen, relative formula mass 28, gives two moles of ammonia, relative formula mass 17. Calculate the theoretical mass of ammonia from 28 g of nitrogen.

    Model answer

    28 ÷ 28 = 1.0 mol of nitrogen gives 2.0 mol of ammonia, so 2.0 × 17 = 34 g, given to 2 significant figures.

  6. 6

    Two moles of hydrogen, relative formula mass 2, give two moles of water, relative formula mass 18. Calculate the theoretical mass of water from 4.0 g of hydrogen.

    Model answer

    4.0 ÷ 2 = 2.0 mol of hydrogen gives 2.0 mol of water, so 2.0 × 18 = 36 g, given to 2 significant figures.

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Monitoring and Controlling Chemical Reactions

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AThe products sit at a higher energy level than the reactants.
BThe activation energy, the energy that must be supplied before the reaction can happen.
CThe reactants, the products, the activation energy and the overall energy change.

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