levo

Redox and Electrochemistry

Predicting Redox Reactions from Electrode Potentials

  • 3 things to know
  • Papers 1 and 3

Overview

Using E° values to decide which species is oxidised, and why a feasible reaction may still be slow.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

Given E°(Cl₂/Cl⁻) = +1.36 V and E°(Br₂/Br⁻) = +1.09 V, which is the stronger oxidising agent, chlorine or bromine?

Key term

Given E°(Zn²⁺/Zn) = −0.76 V and E°(Fe²⁺/Fe) = −0.44 V, which metal is the stronger reducing agent, zinc or iron?

Key term

Given E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V, what is the EMF for the reaction Zn + Cu²⁺ → Zn²⁺ + Cu?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Given E°(Cl₂/Cl⁻) = +1.36 V and E°(Br₂/Br⁻) = +1.09 V, which is the stronger oxidising agent, chlorine or bromine?

    Model answer

    Chlorine is the stronger oxidising agent, because the Cl₂/Cl⁻ half-cell has the more positive electrode potential, so Cl₂ is more readily reduced.

  2. 2

    Given E°(Zn²⁺/Zn) = −0.76 V and E°(Fe²⁺/Fe) = −0.44 V, which metal is the stronger reducing agent, zinc or iron?

    Model answer

    Zinc is the stronger reducing agent, because the Zn²⁺/Zn half-cell has the more negative electrode potential, so zinc is more readily oxidised.

  3. 3

    Given E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V, what is the EMF for the reaction Zn + Cu²⁺ → Zn²⁺ + Cu?

    Model answer

    EMF = +0.34 − (−0.76) = +1.10 V, because Cu²⁺ is reduced and Zn is oxidised.

  4. 4

    Given E°(Ag⁺/Ag) = +0.80 V and E°(Cu²⁺/Cu) = +0.34 V, will silver metal reduce Cu²⁺ ions under standard conditions?

    Model answer

    No; EMF = +0.34 − (+0.80) = −0.46 V, which is negative, so the reaction is not feasible.

  5. 5

    How do you use standard electrode potentials to predict whether a redox reaction is feasible?

    Model answer

    Calculate the EMF for the reaction as written by subtracting the electrode potential of the half-cell where oxidation occurs from that of the half-cell where reduction occurs; a positive EMF indicates the reaction is feasible.

  6. 6

    If the calculated EMF of a cell is positive, what does this indicate about the feasibility of the reaction?

    Model answer

    A positive EMF indicates the reaction is thermodynamically feasible and can occur spontaneously.

Other ways to work this

The same content, four other ways.

What is inside Levo

Six ways to work the same material.

1Closed book
2Open book
3Closed book

The 3-step method, run for you

Answer cold, learn it, then prove it stuck. Levo tracks the jump between your first attempt and your last.

Atomic Structure
Amount of Substance
Bonding
Energetics and Thermodynamics

Cram a whole paper in one sitting

Sort every topic into what you know and what you do not, then drill only the weak ones.

A atom.
nitrogencarbonsulfur

Blank Blitz makes facts automatic

Rapid timed gap-fills on the terms and numbers you need to recall without thinking.

AOxidation is the loss of electrons.
BReduction is the gain of electrons.
CAn oxidising agent is an electron acceptor.

Build It gets the exam shape right

Assemble a full-mark answer from its marking points, in the order an examiner wants them.

The sum of all mole fractions equals 1.
TrueFalse

Test It catches misconceptions

Spot the fault in a statement. The traps are the mistakes students actually make.

721941163128510

Brain Breaks between sessions

Short focus games to reset attention, so the next set lands better than the last.

Every question in Redox and Electrochemistry, on a schedule.

Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.

Or £46 a year, about £3.83 a month. Cancel anytime.