AQA A-Level Chemistry 7405
Atomic Structure
Amount of Substance
Bonding
Energetics and Thermodynamics
Kinetics
Chemical Equilibria
Redox and Electrochemistry
Acids and Bases
Periodicity and Group Chemistry
Period 3 Elements and Their Oxides
Transition Metals
Introduction to Organic Chemistry
Hydrocarbons
Halogenoalkanes, Alcohols and Organic Analysis
Carbonyls, Carboxylic Acids and Derivatives
Aromatic Chemistry and Amines
Polymers, Amino Acids, Proteins and DNA
Organic Synthesis, NMR and Chromatography
Redox and Electrochemistry
Predicting Redox Reactions from Electrode Potentials
- 3 things to know
- Papers 1 and 3
Overview
Using E° values to decide which species is oxidised, and why a feasible reaction may still be slow.
What you need to know
Answer each one before you reveal it.
Given E°(Zn²⁺/Zn) = −0.76 V and E°(Fe²⁺/Fe) = −0.44 V, which metal is the stronger reducing agent, zinc or iron?
Given E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V, what is the EMF for the reaction Zn + Cu²⁺ → Zn²⁺ + Cu?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Given E°(Cl₂/Cl⁻) = +1.36 V and E°(Br₂/Br⁻) = +1.09 V, which is the stronger oxidising agent, chlorine or bromine?
Model answer
Chlorine is the stronger oxidising agent, because the Cl₂/Cl⁻ half-cell has the more positive electrode potential, so Cl₂ is more readily reduced.
- 2
Given E°(Zn²⁺/Zn) = −0.76 V and E°(Fe²⁺/Fe) = −0.44 V, which metal is the stronger reducing agent, zinc or iron?
Model answer
Zinc is the stronger reducing agent, because the Zn²⁺/Zn half-cell has the more negative electrode potential, so zinc is more readily oxidised.
- 3
Given E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V, what is the EMF for the reaction Zn + Cu²⁺ → Zn²⁺ + Cu?
Model answer
EMF = +0.34 − (−0.76) = +1.10 V, because Cu²⁺ is reduced and Zn is oxidised.
- 4
Given E°(Ag⁺/Ag) = +0.80 V and E°(Cu²⁺/Cu) = +0.34 V, will silver metal reduce Cu²⁺ ions under standard conditions?
Model answer
No; EMF = +0.34 − (+0.80) = −0.46 V, which is negative, so the reaction is not feasible.
- 5
How do you use standard electrode potentials to predict whether a redox reaction is feasible?
Model answer
Calculate the EMF for the reaction as written by subtracting the electrode potential of the half-cell where oxidation occurs from that of the half-cell where reduction occurs; a positive EMF indicates the reaction is feasible.
- 6
If the calculated EMF of a cell is positive, what does this indicate about the feasibility of the reaction?
Model answer
A positive EMF indicates the reaction is thermodynamically feasible and can occur spontaneously.
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