AQA GCSE Combined Science Physics 8464
Atomic Structure
Electricity
Energy
Forces
Magnetism and Electromagnetism
Particle Model of Matter
Forces
Area under a velocity-time graph, and the uniform acceleration equation
- 3 things to know
- Physics Paper 2
Overview
Finding distance from the area under a curved velocity-time line, the equation linking final velocity, initial velocity, acceleration and distance, free fall at 9.8 m/s², and terminal velocity.
What you need to know
Answer each one before you reveal it.
State in words the equation linking final velocity, initial velocity, acceleration and distance for uniform acceleration.
Write the uniform acceleration equation using the symbols v, u, a and s.
Questions from this subtopic
Each one with the model answer underneath.
- 1
How can the distance travelled be found when a velocity–time line is curved rather than straight?
Model answer
By counting the squares under the curve and multiplying by the distance each square represents.
- 2
On a velocity–time graph each square represents 2 m/s along one side and 1 s along the other. What distance does one square represent?
Model answer
Each square represents 2 m, because 2 m/s × 1 s = 2 m.
- 3
To what kind of motion does the equation linking final velocity, initial velocity, acceleration and distance apply?
Model answer
It applies only to motion with uniform, that is constant, acceleration.
- 4
State in words the equation linking final velocity, initial velocity, acceleration and distance for uniform acceleration.
Model answer
Final velocity squared minus initial velocity squared = 2 × acceleration × distance.
- 5
Write the uniform acceleration equation using the symbols v, u, a and s.
Model answer
v² − u² = 2as.
- 6
A car starts from rest and accelerates uniformly at 2 m/s² over a distance of 100 m. Calculate its final velocity.
Model answer
The final velocity is 20 m/s, because v² = 2 × 2 m/s² × 100 m = 400.
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