OCR A-Level Physics A H556
Practical Skills in the Written Papers
The Practical Endorsement
Physical Quantities and Units
Making Measurements and Analysing Data
Nature of Quantities
Motion
Forces in Action
Work, Energy and Power
Materials
Newton’s Laws of Motion and Momentum
Charge and Current
Energy, Power and Resistance
Electrical Circuits
Waves
Quantum Physics
Thermal Physics
Oscillations
Gravitational Fields
Astrophysics and Cosmology
Capacitors
Electric Fields
Electromagnetism
Nuclear and Particle Physics
Electric Fields
Uniform fields, parallel plates and permittivity
- 3 things to know
- Papers 1, 2 and 3
Overview
Recall questions on uniform field strength E = V/d with calculations, capacitance of a parallel plate capacitor, relative permittivity, and the motion of charged particles in a uniform electric field.
What you need to know
Answer each one before you reveal it.
State the relationship between electric field strength, potential difference, and plate separation in a uniform electric field.
Write the equation for uniform electric field strength between parallel plates and define each symbol.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Calculate the electric field strength when potential difference = 400 V, plate separation = 0.044 m.
Model answer
Electric field strength = 400 ÷ 0.044 = 9090 V m⁻¹.
- 2
State the relationship between electric field strength, potential difference, and plate separation in a uniform electric field.
Model answer
The electric field strength equals the potential difference divided by the separation of the plates.
- 3
Write the equation for uniform electric field strength between parallel plates and define each symbol.
Model answer
E = V/d, where E is electric field strength, V is the potential difference between the plates, and d is the separation of the plates.
- 4
What quantities are needed to calculate the electric field strength in a uniform field between parallel plates?
Model answer
The potential difference between the plates (V) and the separation of the plates (d).
- 5
Write the equation for the capacitance of a parallel plate capacitor with a vacuum between the plates.
Model answer
C = ε₀A/d, where C is capacitance, ε₀ is the permittivity of free space, A is the plate area, and d is the plate separation.
- 6
How does the capacitance equation for a parallel plate capacitor change when a dielectric is inserted between the plates?
Model answer
The permittivity of free space (ε₀) is replaced by the permittivity of the dielectric material (ε), giving C = εA/d.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Electric Fields, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.