OCR A-Level Physics A H556
Practical Skills in the Written Papers
The Practical Endorsement
Physical Quantities and Units
Making Measurements and Analysing Data
Nature of Quantities
Motion
Forces in Action
Work, Energy and Power
Materials
Newton’s Laws of Motion and Momentum
Charge and Current
Energy, Power and Resistance
Electrical Circuits
Waves
Quantum Physics
Thermal Physics
Oscillations
Gravitational Fields
Astrophysics and Cosmology
Capacitors
Electric Fields
Electromagnetism
Nuclear and Particle Physics
Nuclear and Particle Physics
Binding energy per nucleon and induced fission
- 1 thing to know
- Papers 1, 2 and 3
Overview
Recall questions on binding energy per nucleon and its calculation, the binding energy curve and iron-56, why fusion and fission release energy, induced fission, chain reactions and slowing neutrons.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define binding energy per nucleon.
Model answer
The total binding energy of a nucleus divided by its nucleon number A.
- 2
How is binding energy per nucleon calculated from total binding energy?
Model answer
By dividing the total binding energy E_B by the nucleon number A.
- 3
Calculate the binding energy per nucleon when binding energy = 3.17 × 10⁻¹¹ J, nucleon number = 24.
Model answer
Binding energy per nucleon = 3.17 × 10⁻¹¹ ÷ 24 = 1.32 × 10⁻¹² J.
- 4
Describe how binding energy per nucleon varies with nucleon number across the periodic table.
Model answer
It increases rapidly for light nuclei, reaches a maximum around A ≈ 56 (iron-56), then decreases gradually for heavier nuclei.
- 5
Which nucleus has the highest binding energy per nucleon?
Model answer
Nickel-62 (⁶²Ni), narrowly ahead of iron-56 (⁵⁶Fe), which is usually quoted as the peak.
- 6
Why is iron-56 considered the most stable nucleus?
Model answer
Because its binding energy per nucleon is at the peak of the curve (only nickel-62 is very slightly higher), so a great deal of energy per nucleon would be required to separate its nucleons.
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