OCR A-Level Physics A H556
Practical Skills in the Written Papers
The Practical Endorsement
Physical Quantities and Units
Making Measurements and Analysing Data
Nature of Quantities
Motion
Forces in Action
Work, Energy and Power
Materials
Newton’s Laws of Motion and Momentum
Charge and Current
Energy, Power and Resistance
Electrical Circuits
Waves
Quantum Physics
Thermal Physics
Oscillations
Gravitational Fields
Astrophysics and Cosmology
Capacitors
Electric Fields
Electromagnetism
Nuclear and Particle Physics
Electrical Circuits
Kirchhoff's laws and combining resistances
- 4 things to know
- Papers 2 and 3
Overview
Recall questions on Kirchhoff's first and second laws and the conservation principles behind them, resistors in series and parallel with calculations, and how current and potential difference are shared in series and parallel circuits.
What you need to know
Answer each one before you reveal it.
What fundamental conservation principle underlies Kirchhoff's second law?
Kirchhoff's first law is a consequence of which conservation principle?
How is the total potential difference shared in a series circuit?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State Kirchhoff's second law.
Model answer
The sum of the electromotive forces in any closed loop equals the sum of the potential differences across all components in that loop.
- 2
What fundamental conservation principle underlies Kirchhoff's second law?
Model answer
Conservation of energy.
- 3
Kirchhoff's first law is a consequence of which conservation principle?
Model answer
Conservation of charge.
- 4
Write the formula for the total resistance of resistors connected in series.
Model answer
R = R₁ + R₂ + …
- 5
Explain why the total resistance of resistors in series equals the sum of the individual resistances.
Model answer
In series, the same current flows through each resistor, and the total potential difference is the sum of the p.d.s across each. Applying V = IR to each resistor and summing gives R_total = R₁ + R₂ + …
- 6
Calculate the total resistance when resistors of 930 Ω and 40 Ω are connected in series.
Model answer
Total resistance = 930 + 40 = 970 Ω.
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