OCR A-Level Physics A H556
Practical Skills in the Written Papers
The Practical Endorsement
Physical Quantities and Units
Making Measurements and Analysing Data
Nature of Quantities
Motion
Forces in Action
Work, Energy and Power
Materials
Newton’s Laws of Motion and Momentum
Charge and Current
Energy, Power and Resistance
Electrical Circuits
Waves
Quantum Physics
Thermal Physics
Oscillations
Gravitational Fields
Astrophysics and Cosmology
Capacitors
Electric Fields
Electromagnetism
Nuclear and Particle Physics
Gravitational Fields
Field strength of a point mass and the uniform field near Earth
- 3 things to know
- Papers 1, 2 and 3
Overview
Recall questions on gravitational field strength g = −GM/r² for a point mass with calculations, why the field is approximately uniform near the Earth's surface, and why g equals the acceleration of free fall.
What you need to know
Answer each one before you reveal it.
In the equation g = −GM/r², what physical quantity does M represent?
Which formula is used to calculate the gravitational field strength at a given distance from a point mass?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation for gravitational field strength at a distance from a point mass and define each term.
Model answer
g = −GM/r², where G is the gravitational constant, M is the mass creating the field, and r is the distance from the centre of the mass.
- 2
In the equation g = −GM/r², what physical quantity does M represent?
Model answer
The mass of the object creating the gravitational field.
- 3
Which formula is used to calculate the gravitational field strength at a given distance from a point mass?
Model answer
g = GM/r², where G is the gravitational constant, M is the mass, and r is the distance from the centre of the mass.
- 4
Calculate the gravitational field strength when gravitational constant = 6.67 × 10⁻¹¹ N m² kg⁻², mass = 8.13 × 10²⁵ kg, distance from centre = 4.66 × 10⁷ m.
Model answer
Gravitational field strength = (6.67 × 10⁻¹¹ × 8.13 × 10²⁵) ÷ (4.66 × 10⁷)² = 2.50 N kg⁻¹.
- 5
Why is the gravitational field strength approximately uniform close to the Earth's surface?
Model answer
Because the change in distance from the Earth's centre is negligible compared to the Earth's radius, so r remains effectively constant.
- 6
What condition must be met for the gravitational field to be considered uniform near a planetary surface?
Model answer
The height above the surface must be negligible compared to the planet's radius, so the distance from the centre remains approximately constant.
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