AQA GCSE Combined Science Chemistry 8464
Atomic Structure and the Periodic Table
Bonding, Structure, and the Properties of Matter
Chemical Analysis
Chemical Changes
Chemistry of the Atmosphere
Energy Changes
Organic Chemistry
Quantitative Chemistry
The Rate and Extent of Chemical Change
Atomic Structure and the Periodic Table
Relative atomic mass and electronic structure
- 3 things to know
- Chemistry Paper 1
Overview
Relative atomic mass as an average over isotopes, why chlorine is 35.5, calculating relative atomic mass from percentage abundances, how electrons fill the lowest energy levels or shells first, and writing electronic structures such as 2,8,1 for sodium and 2,8,7 for chlorine.
What you need to know
Answer each one before you reveal it.
Describe the method for calculating a relative atomic mass from percentage abundances.
How many electrons fill the lowest energy level of an atom?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is the relative atomic mass of an element?
Model answer
It is an average value that takes account of the abundance of each isotope of the element.
- 2
Explain why the relative atomic mass of chlorine is 35.5 rather than a whole number.
Model answer
Because chlorine is a mixture of isotopes of mass 35 and 37, and the average weighted by their abundances falls between them.
- 3
Which two pieces of information about an element's isotopes are needed to find its relative atomic mass?
Model answer
The mass number of each isotope and the abundance of each isotope.
- 4
Describe the method for calculating a relative atomic mass from percentage abundances.
Model answer
Multiply each isotope's mass number by its percentage abundance, add the results together and divide by 100.
- 5
An element is 90% atoms of mass number 20 and 10% atoms of mass number 22. Calculate its relative atomic mass.
Model answer
It is 20.2, from (90 × 20 + 10 × 22) ÷ 100.
- 6
Boron is 20% boron-10 and 80% boron-11. Calculate the relative atomic mass of boron.
Model answer
It is 10.8, from (20 × 10 + 80 × 11) ÷ 100.
Other ways to work this
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