AQA GCSE Combined Science Chemistry 8464
Atomic Structure and the Periodic Table
Bonding, Structure, and the Properties of Matter
Chemical Analysis
Chemical Changes
Chemistry of the Atmosphere
Energy Changes
Organic Chemistry
Quantitative Chemistry
The Rate and Extent of Chemical Change
Quantitative Chemistry
Relative formula mass and concentration of solutions
- 3 things to know
- Chemistry Paper 1
Overview
Defining and calculating relative formula mass, showing both sides of a balanced equation total the same, percentage by mass of an element, and concentration in g/dm³ from the mass of solute and the volume of solution.
What you need to know
Answer each one before you reveal it.
Calculate the percentage by mass of nitrogen in NH₄NO₃, given relative atomic masses N = 14, H = 1 and O = 16.
In which unit is the concentration of a solution given when it is measured as a mass in a given volume?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the relative formula mass of a compound.
Model answer
It is the sum of the relative atomic masses of all the atoms shown in the formula of the compound.
- 2
Calculate the relative formula mass of CO₂, given relative atomic masses C = 12 and O = 16.
Model answer
44.
- 3
Calculate the relative formula mass of H₂SO₄, given relative atomic masses H = 1, S = 32 and O = 16.
Model answer
98.
- 4
How does the total of the relative formula masses of the reactants compare with that of the products in a balanced equation?
Model answer
They are equal, provided each formula is counted the number of times shown by its balancing number.
- 5
For 2H₂ + O₂ → 2H₂O, show that the totals of relative formula mass are the same on both sides, given H = 1 and O = 16.
Model answer
The reactants total 2 × 2 + 32 = 36 and the products total 2 × 18 = 36, so both sides come to 36.
- 6
How is the percentage by mass of an element in a compound calculated?
Model answer
Divide the total relative atomic mass of that element in the formula by the relative formula mass of the compound, then multiply by 100.
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