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Alkenes

Alkenes: the double bond, sigma and pi bonding, and shape

  • 1 thing to know
  • Components 02 and 03

Overview

Recall questions on unsaturation, how the sigma and pi bonds form, why there is no free rotation, and the trigonal planar shape and its angle.

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Answer each one before you reveal it.

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Key term

Why is there no free rotation about the carbon-carbon double bond in alkenes?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What does it mean for alkenes to be described as unsaturated hydrocarbons?

    Model answer

    They contain fewer than the maximum number of hydrogen atoms per carbon atom due to the presence of a carbon-carbon double bond.

  2. 2

    What two types of bond make up the carbon-carbon double bond in an alkene?

    Model answer

    One sigma (σ) bond and one pi (π) bond.

  3. 3

    How is a sigma bond formed between two carbon atoms?

    Model answer

    By the direct (head-on) overlap of orbitals along the axis between the two bonding carbon atoms.

  4. 4

    Describe how a pi bond is formed in an alkene.

    Model answer

    By the sideways overlap of adjacent p-orbitals, creating regions of electron density above and below the plane of the bonding carbon atoms.

  5. 5

    Why is there no free rotation about the carbon-carbon double bond in alkenes?

    Model answer

    Rotation would break the sideways overlap of the p-orbitals that form the pi bond.

  6. 6

    What is the shape around each carbon atom involved in the C=C double bond of an alkene?

    Model answer

    Trigonal planar.

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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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