OCR A-Level Chemistry H432
Foundations in Chemistry
Bonding and Structure
Periodic Table and Energy
Enthalpy Changes
Chemical Equilibrium
Basic Concepts of Organic Chemistry
Core Organic Chemistry
Alkenes
Organic Synthesis
How Fast?
Physical Chemistry and Transition Elements
Acids, Bases and Buffers
Redox and Electrode Potentials
Transition Elements
Aromatic Compounds
Organic Chemistry and Analysis
Spectroscopy
How Fast?
Half-life and the rate constant of a first-order reaction
- 2 things to know
- Components 01 and 03
Overview
Recall questions on the constant half-life of a first-order reaction, reading it from a graph, and k = ln 2 / t½.
What you need to know
Answer each one before you reveal it.
What equation links k to the half-life, when does it apply, and what is k when t½ = 280 s?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the key characteristic of the half-life of a first-order reaction.
Model answer
The half-life is constant regardless of the initial concentration.
- 2
Why does a first-order reaction have a constant half-life?
Model answer
Because the rate depends only on the first power of concentration, so the time for concentration to halve is independent of the starting concentration.
- 3
How can the half-life of a first-order reaction be determined from a concentration–time graph?
Model answer
By measuring the time taken for the concentration to fall to half its value; this time remains constant throughout the reaction.
- 4
If you measure successive half-lives from a concentration–time graph and find they are all equal, what does this indicate about the reaction order?
Model answer
The reaction is first-order with respect to that reactant.
- 5
State the equation relating the rate constant k to the half-life t½ for a first-order reaction.
Model answer
k = ln 2 / t½
- 6
In the equation k = ln 2 / t½, what does each symbol represent?
Model answer
k is the rate constant, ln 2 is the natural logarithm of 2 (approximately 0.693), and t½ is the half-life of the reaction.
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