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Foundations in Chemistry

Stoichiometry, percentage yield and atom economy

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on the steps of a reacting-mass calculation, theoretical and percentage yield, and calculating atom economy.

What you need to know

Answer each one before you reveal it.

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Numbers

What amount of gas occupies 0.0045 m³ at 169000 Pa and 233 K (R = 8.315 J K⁻¹ mol⁻¹), and what are the first and last steps of a reacting-mass calculation?

Numbers

How is percentage yield calculated, what is the percentage yield for an actual yield of 79.5 g and a theoretical yield of 80.5 g, and what is theoretical yield?

Numbers

How is atom economy calculated, which apparatus is used to prepare a standard solution accurately, and which mathematical tools are used in composition calculations?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What do stoichiometric relationships in balanced equations show?

    Model answer

    The molar ratios in which reactants combine and products form.

  2. 2

    When using stoichiometry to calculate reacting masses, what is the first step?

    Model answer

    Convert the known mass to moles using n = m/M.

  3. 3

    After converting mass to moles in a stoichiometry calculation, what do you do next?

    Model answer

    Apply the molar ratio from the balanced equation.

  4. 4

    What is the final step when calculating reacting masses using stoichiometry?

    Model answer

    Convert moles to mass using m = n × M.

  5. 5

    State the formula for calculating percentage yield.

    Model answer

    Percentage yield = (actual yield / theoretical yield) × 100.

  6. 6

    Calculate the percentage yield when actual yield = 79.5 g, theoretical yield = 80.5 g.

    Model answer

    Percentage yield = (79.5 ÷ 80.5) × 100 = 98.8 %.

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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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