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Chemical Equilibrium

The equilibrium constant, Kc

  • 2 things to know
  • Components 01 and 03

Overview

Recall questions on where products and reactants sit in the Kc expression, and what a value much greater than, close to, or much less than 1 tells you.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

How are the concentrations of each species treated in the Kc expression with respect to the balanced equation?

Key term

What can you deduce about the composition of an equilibrium mixture when Kc is approximately equal to 1?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    In the expression for Kc, where do the equilibrium concentrations of products appear?

    Model answer

    In the numerator.

  2. 2

    How are the concentrations of each species treated in the Kc expression with respect to the balanced equation?

    Model answer

    Each concentration is raised to the power of its stoichiometric coefficient in the balanced equation.

  3. 3

    If a reaction has a small value of Kc, what does this tell you about the equilibrium mixture?

    Model answer

    The equilibrium position lies to the left, favouring reactants.

  4. 4

    What can you deduce about the composition of an equilibrium mixture when Kc is approximately equal to 1?

    Model answer

    Significant amounts of both reactants and products are present at equilibrium.

  5. 5

    Explain what it means for a reaction if its Kc value is much greater than 1.

    Model answer

    The reaction goes almost to completion, with the equilibrium mixture containing predominantly products.

  6. 6

    Why does a very large Kc indicate that almost all reactants have been converted to products?

    Model answer

    Because a large Kc means the ratio of product concentrations to reactant concentrations is very high, indicating the equilibrium lies far to the right.

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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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