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Organic Chemistry and Analysis

Test-tube tests for the organic functional groups

  • 2 things to know
  • Components 02 and 03

Overview

Recall questions on the tests for alkenes, haloalkanes, phenols, carbonyls, aldehydes against ketones, alcohols and carboxylic acids.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Key term

How are haloalkanes identified, and what colour precipitates do a chloroalkane and an iodoalkane give with silver nitrate?

Process

What species is present in Tollens' reagent, how does acidified potassium dichromate test alcohols, and what happens when an aldehyde is warmed with acidified potassium dichromate?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What observation indicates a positive test for an alkene using bromine water?

    Model answer

    The orange bromine water decolourises (turns colourless) as bromine adds across the C=C double bond.

  2. 2

    Describe the test used to identify haloalkanes.

    Model answer

    Warm the haloalkane with aqueous silver nitrate in ethanol; a precipitate of silver halide forms.

  3. 3

    What colour precipitate forms when a chloroalkane is tested with silver nitrate in ethanol?

    Model answer

    A white precipitate of silver chloride.

  4. 4

    What colour precipitate forms when an iodoalkane is tested with silver nitrate in ethanol?

    Model answer

    A yellow precipitate of silver iodide.

  5. 5

    How can phenols be distinguished from carboxylic acids using chemical tests?

    Model answer

    Phenols dissolve in sodium hydroxide solution but do not react with carbonates to produce carbon dioxide, whereas carboxylic acids react with carbonates to release CO₂.

  6. 6

    What reagent is used to identify carbonyl compounds, and what is the positive result?

    Model answer

    2,4-dinitrophenylhydrazine (2,4-DNP); a positive result is an orange or yellow precipitate.

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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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