OCR A-Level Chemistry H432
Foundations in Chemistry
Bonding and Structure
Periodic Table and Energy
Enthalpy Changes
Chemical Equilibrium
Basic Concepts of Organic Chemistry
Core Organic Chemistry
Alkenes
Organic Synthesis
How Fast?
Physical Chemistry and Transition Elements
Acids, Bases and Buffers
Redox and Electrode Potentials
Transition Elements
Aromatic Compounds
Organic Chemistry and Analysis
Spectroscopy
Enthalpy Changes
Calorimetry and correcting for heat loss
- 2 things to know
- Components 01 and 03
Overview
Recall questions on q = mcΔT in practice, why a polystyrene cup and a lid are used, why stirring matters, and correcting for heat loss by extrapolation.
What you need to know
Answer each one before you reveal it.
What does graphical extrapolation allow you to determine in a calorimetry experiment?
Questions from this subtopic
Each one with the model answer underneath.
- 1
How can enthalpy changes be determined directly?
Model answer
By calorimetry experiments that measure temperature changes.
- 2
When is it appropriate to determine an enthalpy change indirectly using Hess' law?
Model answer
When direct measurement is impractical.
- 3
State the formula used in calorimetry to calculate the heat absorbed or released.
Model answer
q = mcΔT
- 4
In the equation q = mcΔT, what does each symbol represent?
Model answer
q = heat energy transferred, m = mass of substance being heated, c = specific heat capacity, ΔT = temperature change.
- 5
State the formula for calculating the enthalpy change of reaction using combustion data, including stoichiometric coefficients.
Model answer
ΔrH = Σn·ΔcH(reactants) − Σn·ΔcH(products), where n represents stoichiometric coefficients.
- 6
Calculate the enthalpy change of reaction when moles of reactant 1 = 1, combustion enthalpy of reactant 1 = -283 kJ mol⁻¹, moles of reactant 2 = 2, combustion enthalpy of reactant 2 = -286 kJ mol⁻¹, moles of product 1 = 1, combustion enthalpy of product 1 = -726 kJ mol⁻¹.
Model answer
Enthalpy change of reaction = (1 × -283 + 2 × -286) - (1 × -726) = -129 kJ mol⁻¹.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Enthalpy Changes, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.