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Periodic Table and Energy

Concentration, pressure and measuring reaction rate

  • 2 things to know
  • Components 01 and 03

Overview

Recall questions on why concentration and pressure raise the rate through collision frequency, and on measuring rate from the gradient of a graph.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

Why does raising the concentration or the pressure of the reactants increase the rate of reaction?

Numbers

What does the gradient of a concentration-time graph give, and what does Δt represent in the rate equation?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why does increasing the concentration of reactants lead to a higher reaction rate in terms of particle density?

    Model answer

    Higher concentration means more particles per unit volume, so there are more reactant particles available in a given space to undergo collisions.

  2. 2

    Explain how having more particles in a given volume affects collision behaviour.

    Model answer

    More particles in a given volume leads to more frequent collisions between reacting particles.

  3. 3

    How does an increase in collision frequency affect the number of successful collisions?

    Model answer

    More frequent collisions means more successful collisions per unit time, increasing the rate of reaction.

  4. 4

    What happens to the volume occupied by a gas when its pressure is increased?

    Model answer

    Higher pressure compresses the gas into a smaller volume.

  5. 5

    How does compressing a gas affect the spacing between its particles?

    Model answer

    The particles are closer together when the gas is compressed into a smaller volume.

  6. 6

    Why does increasing the pressure of gaseous reactants increase the rate of reaction?

    Model answer

    When particles are closer together, collision frequency increases, leading to more successful collisions per unit time.

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Foundations in Chemistry
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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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