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Redox and Electrode Potentials

Redox titrations and their calculations

  • 1 thing to know
  • Components 01 and 03

Overview

Recall questions on detecting the end point, why manganate(VII) is self-indicating, and using the mole ratio from the balanced equation.

What you need to know

Answer each one before you reveal it.

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Process

Outline the basis and calculation sequence of a redox titration.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is a redox titration?

    Model answer

    A volumetric analysis technique in which an oxidising agent is titrated against a reducing agent (or vice versa) to determine concentration, using the transfer of electrons as the basis for the reaction.

  2. 2

    What fundamental process forms the basis of the reaction in a redox titration?

    Model answer

    The transfer of electrons between the oxidising agent and reducing agent.

  3. 3

    How can the endpoint of a redox titration be detected?

    Model answer

    Either by a self-indicating colour change of one reactant (e.g. potassium manganate(VII) turning from purple to colourless) or by using a redox indicator.

  4. 4

    Why is potassium manganate(VII) described as self-indicating in redox titrations?

    Model answer

    Because it undergoes a visible colour change from purple to colourless when reduced, eliminating the need for a separate indicator.

  5. 5

    When would a redox indicator be needed in a redox titration?

    Model answer

    When neither reactant undergoes a visible colour change at the endpoint, so an external indicator is required to signal when the reaction is complete.

  6. 6

    Why must the stoichiometry from the balanced redox equation be used in redox titration calculations?

    Model answer

    To balance the moles of electrons transferred and correctly relate the moles of oxidising agent to moles of reducing agent.

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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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