OCR A-Level Chemistry H432
Foundations in Chemistry
Bonding and Structure
Periodic Table and Energy
Enthalpy Changes
Chemical Equilibrium
Basic Concepts of Organic Chemistry
Core Organic Chemistry
Alkenes
Organic Synthesis
How Fast?
Physical Chemistry and Transition Elements
Acids, Bases and Buffers
Redox and Electrode Potentials
Transition Elements
Aromatic Compounds
Organic Chemistry and Analysis
Spectroscopy
Spectroscopy
Molecular formula from the molecular ion, and fragmentation losses
- 1 thing to know
- Components 02 and 03
Overview
Recall questions on scaling an empirical formula with the molecular ion peak, and on what losses of 15, 17, 29 and 45 mass units suggest.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why does the mass spectrum of an organic compound often show a small peak one unit above the molecular ion peak?
Model answer
It is the M+1 peak, caused by the small proportion of molecules that contain a carbon-13 atom.
- 2
When determining molecular formula from empirical formula, what must first be calculated?
Model answer
The mass of the empirical formula must be calculated.
- 3
How is the molecular ion peak (M⁺) from mass spectrometry used with the empirical formula mass?
Model answer
Divide the molecular ion mass by the empirical formula mass to find how many empirical formula units are in the molecular formula.
- 4
Once you know how many empirical formula units are in the molecular formula, how do you obtain the molecular formula?
Model answer
Multiply the empirical formula by this whole number.
- 5
Calculate the multiplier for empirical formula when molecular ion mass = 88, empirical formula mass = 44.
Model answer
Multiplier for empirical formula = 88 ÷ 44 = 2.
- 6
How do fragmentation patterns in mass spectrometry help identify structural features?
Model answer
They show the masses of fragment ions formed when bonds break, indicating which structural units are present in the molecule.
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