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Spectroscopy

Molecular formula from the molecular ion, and fragmentation losses

  • 1 thing to know
  • Components 02 and 03

Overview

Recall questions on scaling an empirical formula with the molecular ion peak, and on what losses of 15, 17, 29 and 45 mass units suggest.

What you need to know

Answer each one before you reveal it.

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Process

When determining molecular formula from empirical formula, what must first be calculated?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why does the mass spectrum of an organic compound often show a small peak one unit above the molecular ion peak?

    Model answer

    It is the M+1 peak, caused by the small proportion of molecules that contain a carbon-13 atom.

  2. 2

    When determining molecular formula from empirical formula, what must first be calculated?

    Model answer

    The mass of the empirical formula must be calculated.

  3. 3

    How is the molecular ion peak (M⁺) from mass spectrometry used with the empirical formula mass?

    Model answer

    Divide the molecular ion mass by the empirical formula mass to find how many empirical formula units are in the molecular formula.

  4. 4

    Once you know how many empirical formula units are in the molecular formula, how do you obtain the molecular formula?

    Model answer

    Multiply the empirical formula by this whole number.

  5. 5

    Calculate the multiplier for empirical formula when molecular ion mass = 88, empirical formula mass = 44.

    Model answer

    Multiplier for empirical formula = 88 ÷ 44 = 2.

  6. 6

    How do fragmentation patterns in mass spectrometry help identify structural features?

    Model answer

    They show the masses of fragment ions formed when bonds break, indicating which structural units are present in the molecule.

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Foundations in Chemistry
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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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