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The ln k against 1/T graph and finding the activation energy

  • 2 things to know
  • Components 01 and 03

Overview

Recall questions on the logarithmic form, which graph is plotted, and what its gradient and intercept give.

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Answer each one before you reveal it.

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Numbers

What does R represent in the Arrhenius equation, which graph is plotted to obtain a straight line, and what does its gradient equal?

Numbers

State the formula used to calculate the pre-exponential factor from the y-intercept of an Arrhenius plot.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    In the logarithmic form of the Arrhenius equation, which term corresponds to the y-variable when plotting a straight-line graph?

    Model answer

    ln k is the y-variable.

  2. 2

    What type of graph is plotted to obtain a straight line from the Arrhenius equation?

    Model answer

    A graph of ln k against 1/T.

  3. 3

    What is the gradient of a graph of ln k against 1/T equal to?

    Model answer

    The gradient equals −Eₐ/R.

  4. 4

    What does the y-intercept of a graph of ln k against 1/T represent?

    Model answer

    The y-intercept equals ln A.

  5. 5

    When determining activation energy graphically, what quantity is plotted on the y-axis?

    Model answer

    ln k is plotted on the y-axis.

  6. 6

    After plotting ln k against 1/T, what must be determined from the graph to find the activation energy?

    Model answer

    The gradient of the straight line must be determined.

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