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Rate-concentration graphs and the initial rates method

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  • Components 01 and 03

Overview

Recall questions on the shapes for zero, first and second order, and on what the gradient of a linear rate-concentration graph gives.

What you need to know

Answer each one before you reveal it.

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Numbers

How is first-order dependence recognised on a rate–concentration graph, why does its gradient give k, and what does a zero-order reactant give?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the shape of a rate–concentration graph for a zero-order reaction with respect to a reactant.

    Model answer

    A horizontal straight line.

  2. 2

    What does a horizontal line on a rate–concentration graph indicate about the reaction order?

    Model answer

    The reaction is zero-order with respect to that reactant; changing its concentration does not affect the rate.

  3. 3

    How can you identify a first-order dependence from a rate–concentration graph?

    Model answer

    The graph is a straight line through the origin, showing rate is directly proportional to concentration.

  4. 4

    Why does a second-order reaction produce a curved rate–concentration graph rather than a straight line?

    Model answer

    Because rate is proportional to concentration squared, so the relationship is non-linear (parabolic).

  5. 5

    For a first-order reaction, how can the rate constant k be determined from a rate–concentration graph?

    Model answer

    k equals the gradient of the straight line on the rate–concentration graph.

  6. 6

    Explain why the gradient of a rate–concentration graph gives the rate constant for a first-order reaction.

    Model answer

    For first-order, rate = k[A], so plotting rate against [A] gives a straight line with gradient k.

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