OCR A-Level Chemistry H432
Foundations in Chemistry
Bonding and Structure
Periodic Table and Energy
Enthalpy Changes
Chemical Equilibrium
Basic Concepts of Organic Chemistry
Core Organic Chemistry
Alkenes
Organic Synthesis
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Physical Chemistry and Transition Elements
Acids, Bases and Buffers
Redox and Electrode Potentials
Transition Elements
Aromatic Compounds
Organic Chemistry and Analysis
Spectroscopy
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Rate-concentration graphs and the initial rates method
- 1 thing to know
- Components 01 and 03
Overview
Recall questions on the shapes for zero, first and second order, and on what the gradient of a linear rate-concentration graph gives.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Describe the shape of a rate–concentration graph for a zero-order reaction with respect to a reactant.
Model answer
A horizontal straight line.
- 2
What does a horizontal line on a rate–concentration graph indicate about the reaction order?
Model answer
The reaction is zero-order with respect to that reactant; changing its concentration does not affect the rate.
- 3
How can you identify a first-order dependence from a rate–concentration graph?
Model answer
The graph is a straight line through the origin, showing rate is directly proportional to concentration.
- 4
Why does a second-order reaction produce a curved rate–concentration graph rather than a straight line?
Model answer
Because rate is proportional to concentration squared, so the relationship is non-linear (parabolic).
- 5
For a first-order reaction, how can the rate constant k be determined from a rate–concentration graph?
Model answer
k equals the gradient of the straight line on the rate–concentration graph.
- 6
Explain why the gradient of a rate–concentration graph gives the rate constant for a first-order reaction.
Model answer
For first-order, rate = k[A], so plotting rate against [A] gives a straight line with gradient k.
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