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Foundations in Chemistry

Gas volumes, concentration and the ideal gas equation

  • 3 things to know
  • Components 01, 02 and 03

Overview

Recall questions on molar gas volume at RTP, concentration in mol dm⁻³ and g dm⁻³, and using pV = nRT with SI units throughout.

What you need to know

Answer each one before you reveal it.

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Numbers

How is the relative atomic mass of chlorine calculated from isotopic masses 35 (75 %) and 37 (25 %)?

Numbers

How is amount of substance calculated from a gas volume, what is molar gas volume, and how is amount calculated from a solution's concentration and volume?

Numbers

What amount is in 1.987 dm³ of 3.92 mol dm⁻³ solution, what is 3.97 mol dm⁻³ in g dm⁻³ when M = 131 g mol⁻¹, and how is pV = nRT rearranged for n?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the formula for calculating amount of substance from gas volume at RTP.

    Model answer

    n = V/Vₘ, where V is volume in dm³ and Vₘ is molar gas volume in dm³ mol⁻¹.

  2. 2

    What does Vₘ represent in the equation n = V/Vₘ?

    Model answer

    Molar gas volume in dm³ mol⁻¹.

  3. 3

    Calculate the amount of substance when gas volume = 78.2 dm³, molar gas volume = 25.7 dm³ mol⁻¹.

    Model answer

    Amount of substance = 78.2 ÷ 25.7 = 3.04 mol.

  4. 4

    State the formula for calculating amount of substance from solution volume and concentration.

    Model answer

    n = c × V, where c is concentration in mol dm⁻³ and V is volume in dm³.

  5. 5

    In the equation n = c × V, what units must V be in?

    Model answer

    dm³.

  6. 6

    Calculate the amount of substance when concentration = 3.92 mol dm⁻³, volume = 1.987 dm³.

    Model answer

    Amount of substance = 3.92 × 1.987 = 7.79 mol.

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AThe first step is Cl• + O₃ → ClO• + O₂.
BThe second step is ClO• + O → Cl• + O₂.
CThe overall equation is O₃ + O → 2O₂.

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In ClO⁻, chlorine has oxidation number +1.
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