OCR A-Level Chemistry H432
Foundations in Chemistry
Bonding and Structure
Periodic Table and Energy
Enthalpy Changes
Chemical Equilibrium
Basic Concepts of Organic Chemistry
Core Organic Chemistry
Alkenes
Organic Synthesis
How Fast?
Physical Chemistry and Transition Elements
Acids, Bases and Buffers
Redox and Electrode Potentials
Transition Elements
Aromatic Compounds
Organic Chemistry and Analysis
Spectroscopy
Foundations in Chemistry
Gas volumes, concentration and the ideal gas equation
- 3 things to know
- Components 01, 02 and 03
Overview
Recall questions on molar gas volume at RTP, concentration in mol dm⁻³ and g dm⁻³, and using pV = nRT with SI units throughout.
What you need to know
Answer each one before you reveal it.
How is amount of substance calculated from a gas volume, what is molar gas volume, and how is amount calculated from a solution's concentration and volume?
What amount is in 1.987 dm³ of 3.92 mol dm⁻³ solution, what is 3.97 mol dm⁻³ in g dm⁻³ when M = 131 g mol⁻¹, and how is pV = nRT rearranged for n?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the formula for calculating amount of substance from gas volume at RTP.
Model answer
n = V/Vₘ, where V is volume in dm³ and Vₘ is molar gas volume in dm³ mol⁻¹.
- 2
What does Vₘ represent in the equation n = V/Vₘ?
Model answer
Molar gas volume in dm³ mol⁻¹.
- 3
Calculate the amount of substance when gas volume = 78.2 dm³, molar gas volume = 25.7 dm³ mol⁻¹.
Model answer
Amount of substance = 78.2 ÷ 25.7 = 3.04 mol.
- 4
State the formula for calculating amount of substance from solution volume and concentration.
Model answer
n = c × V, where c is concentration in mol dm⁻³ and V is volume in dm³.
- 5
In the equation n = c × V, what units must V be in?
Model answer
dm³.
- 6
Calculate the amount of substance when concentration = 3.92 mol dm⁻³, volume = 1.987 dm³.
Model answer
Amount of substance = 3.92 × 1.987 = 7.79 mol.
Other ways to work this
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