AQA A-Level Physics 7408
Measurements and Their Errors
Particles and Radiation
Waves
Mechanics and Materials
Electricity
Further Mechanics and Thermal Physics
Fields and Their Consequences
Nuclear Physics
AstrophysicsOptional topic
Medical PhysicsOptional topic
Engineering PhysicsOptional topic
Turning Points in PhysicsOptional topic
ElectronicsOptional topic
Fields and Their Consequences
Energy stored by a capacitor
- 3 things to know
- Papers 2 and 3
Overview
The three energy formulae, and finding the energy from the area under a charge-voltage graph.
What you need to know
Answer each one before you reveal it.
What does E = ½Q²/C mean, and how is E = ½CV² derived from E = ½QV?
What does the gradient of a charge against potential difference graph give, and what shape is it?
Questions from this subtopic
Each one with the model answer underneath.
- 1
How can the energy stored by a capacitor be determined from a graph of charge against potential difference?
Model answer
The energy stored equals the area under the graph of charge against potential difference.
- 2
State the formula for the energy stored by a capacitor in terms of charge and potential difference.
Model answer
E = ½QV, where E is energy, Q is charge and V is potential difference.
- 3
In the equation E = ½QV for capacitor energy, what does each symbol represent?
Model answer
E represents energy stored, Q represents charge stored on the capacitor, and V represents the potential difference across the capacitor.
- 4
Calculate the energy stored when charge = 0.0067 C, potential difference = 97 V.
Model answer
Energy stored = 0.5 × 0.0067 × 97 = 0.325 J.
- 5
In the equation E = ½CV², identify what each term represents.
Model answer
E is the energy stored, C is the capacitance of the capacitor, and V is the potential difference across it.
- 6
Calculate the energy stored when capacitance = 0.000669 F, potential difference = 6 V.
Model answer
Energy stored = 0.5 × 0.000669 × 6 × 6 = 0.012 J.
Other ways to work this
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