Edexcel A-Level Physics 9PH0
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Electric and Magnetic Fields
Charging and discharging graphs and the time constant
- 2 things to know
- Papers 1 and 3
Overview
Recall questions on the shapes of the charge, current and potential difference graphs, why the charging current falls, and the meaning of the time constant.
What you need to know
Answer each one before you reveal it.
What is the equation for the charge remaining on a discharging capacitor, and what linear form does taking logarithms give?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What shape is the graph of potential difference against time for a capacitor discharging through a resistor?
Model answer
It starts at the initial potential difference and falls steeply at first, then more and more slowly, approaching zero asymptotically in an exponential decay.
- 2
How does the current vary with time when a capacitor charges through a resistor?
Model answer
The current starts at a maximum value of V₀/R and then decays exponentially towards zero.
- 3
What shape is the charge against time graph while a capacitor charges through a resistor?
Model answer
The charge rises steeply from zero and then levels off, approaching the final value Q₀ = CV₀ asymptotically.
- 4
Why does the charging current fall as a capacitor charges?
Model answer
As charge accumulates the potential difference across the capacitor rises, so the potential difference across the resistor falls and the current, which equals that potential difference divided by R, falls with it.
- 5
What is meant by the time constant of a resistor-capacitor circuit?
Model answer
It is the product RC, the time taken for the charge, current or potential difference to fall to 1/e, about 37%, of its initial value during discharge.
- 6
Why does the product of resistance and capacitance have the unit of time?
Model answer
Ω × F = (V A⁻¹) × (C V⁻¹) = C A⁻¹ = s, since one ampere is one coulomb per second.
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