Edexcel A-Level Physics 9PH0
Working as a Physicist
Mechanics
Electric Circuits
Materials
Waves and Particle Nature of Light
Further Mechanics
Electric and Magnetic Fields
Nuclear and Particle Physics
Thermodynamics
Space
Nuclear Radiation
Gravitational Fields
Oscillations
Nuclear and Particle Physics
Particle energy units and relativistic lifetimes
- 2 things to know
- Papers 1 and 3
Overview
Recall questions on the electronvolt, MeV and MeV/c², converting between them and SI units, and why fast muons made high in the atmosphere reach the ground.
What you need to know
Answer each one before you reveal it.
Would an observer travelling alongside a fast muon measure its lifetime as extended?
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the electronvolt:
Model answer
One electronvolt is the energy transferred when an electron moves through a potential difference of one volt, equal to 1.60 × 10⁻¹⁹ J.
- 2
How many joules are there in 1 MeV?
Model answer
1 MeV is 10⁶ × 1.60 × 10⁻¹⁹ = 1.60 × 10⁻¹³ J.
- 3
What is an energy of 2.5 GeV in joules?
Model answer
2.5 GeV is 2.5 × 10⁹ × 1.60 × 10⁻¹⁹ = 4.0 × 10⁻¹⁰ J.
- 4
Why is MeV/c² a valid unit of mass?
Model answer
Rearranging the mass–energy relationship gives m = E/c², so an energy divided by c² has the dimensions of mass, and a particle whose rest energy is 1 MeV therefore has a mass of 1 MeV/c².
- 5
A proton has a mass of 938 MeV/c². What is this in kilograms?
Model answer
Its rest energy is 938 × 10⁶ × 1.60 × 10⁻¹⁹ = 1.50 × 10⁻¹⁰ J, and dividing by c² = 9.00 × 10¹⁶ m² s⁻² gives a mass of 1.67 × 10⁻²⁷ kg.
- 6
How do you convert a mass given in kilograms into MeV/c²?
Model answer
Multiply the mass by c² to find the rest energy in joules, then divide by 1.60 × 10⁻¹³ to express that energy in MeV.
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