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Nuclear and Particle Physics

Particle energy units and relativistic lifetimes

  • 2 things to know
  • Papers 1 and 3

Overview

Recall questions on the electronvolt, MeV and MeV/c², converting between them and SI units, and why fast muons made high in the atmosphere reach the ground.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

Why do particle physicists prefer MeV and MeV/c² to joules and kilograms?

Key term

Would an observer travelling alongside a fast muon measure its lifetime as extended?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Define the electronvolt:

    Model answer

    One electronvolt is the energy transferred when an electron moves through a potential difference of one volt, equal to 1.60 × 10⁻¹⁹ J.

  2. 2

    How many joules are there in 1 MeV?

    Model answer

    1 MeV is 10⁶ × 1.60 × 10⁻¹⁹ = 1.60 × 10⁻¹³ J.

  3. 3

    What is an energy of 2.5 GeV in joules?

    Model answer

    2.5 GeV is 2.5 × 10⁹ × 1.60 × 10⁻¹⁹ = 4.0 × 10⁻¹⁰ J.

  4. 4

    Why is MeV/c² a valid unit of mass?

    Model answer

    Rearranging the mass–energy relationship gives m = E/c², so an energy divided by c² has the dimensions of mass, and a particle whose rest energy is 1 MeV therefore has a mass of 1 MeV/c².

  5. 5

    A proton has a mass of 938 MeV/c². What is this in kilograms?

    Model answer

    Its rest energy is 938 × 10⁶ × 1.60 × 10⁻¹⁹ = 1.50 × 10⁻¹⁰ J, and dividing by c² = 9.00 × 10¹⁶ m² s⁻² gives a mass of 1.67 × 10⁻²⁷ kg.

  6. 6

    How do you convert a mass given in kilograms into MeV/c²?

    Model answer

    Multiply the mass by c² to find the rest energy in joules, then divide by 1.60 × 10⁻¹³ to express that energy in MeV.

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