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Further Mechanics

Kinetic energy, momentum and collision calculations

  • 2 things to know
  • Papers 1 and 3

Overview

Recall questions on the derivation of Eₖ = p²/(2m) and its limits, comparing particles of equal energy or equal momentum, and the relative speeds in an elastic collision.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

What is always true of the relative speeds in an elastic collision, what happens when a moving ball collides elastically and head-on with an identical stationary ball, and what happens to kinetic energy when momentum doubles?

Key term

A ball dropped onto a floor rebounds to a lower height than it fell from. What does this tell you about the collision, and why?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why does Eₖ = p²/(2m) only apply to non-relativistic particles?

    Model answer

    It is derived from Eₖ = ½mv², which is only valid when the particle's speed is small compared with the speed of light.

  2. 2

    Two particles have the same kinetic energy but different masses. Which has the greater momentum?

    Model answer

    The more massive particle, because rearranging gives p = √(2mEₖ), so momentum increases with mass at fixed kinetic energy.

  3. 3

    Two particles have the same momentum but different masses. Which has the greater kinetic energy?

    Model answer

    The lighter particle, because Eₖ = p²/(2m) is inversely proportional to mass at fixed momentum.

  4. 4

    A particle's momentum doubles while its mass stays the same. What happens to its kinetic energy?

    Model answer

    It becomes four times larger, because Eₖ is proportional to p².

  5. 5

    An electron of mass 9.11 × 10⁻³¹ kg has a momentum of 2.0 × 10⁻²⁴ kg m s⁻¹. What is its kinetic energy?

    Model answer

    Using Eₖ = p²/(2m), Eₖ = (2.0 × 10⁻²⁴)² ÷ (2 × 9.11 × 10⁻³¹) = 2.2 × 10⁻¹⁸ J.

  6. 6

    A 2.0 kg trolley moving at 3.0 m s⁻¹ collides with a stationary 1.0 kg trolley and the two move off together. How can you show that this collision is inelastic?

    Model answer

    Conservation of momentum gives a common velocity of 6.0 ÷ 3.0 = 2.0 m s⁻¹, and the kinetic energy falls from 9.0 J to 6.0 J, so 3.0 J is not conserved and the collision is inelastic.

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