Edexcel A-Level Physics 9PH0
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Materials
Floating, sinking and upthrust calculations
- 1 thing to know
- Papers 2 and 3
Overview
Recall questions on the condition for floating, the fraction submerged, why a steel ship floats, and finding a volume from apparent loss of weight.
What you need to know
Answer each one before you reveal it.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Why does a steel ship float when the density of steel is about 7800 kg m⁻³?
Model answer
The hull encloses a large volume of air, so the average density of the whole ship is far less than that of water and it displaces enough water to support its weight.
- 2
An object weighs 5.0 N in air and a spring balance reads 3.0 N when it is fully submerged in water. What is the upthrust on it?
Model answer
The upthrust is the difference in the readings, 5.0 − 3.0 = 2.0 N.
- 3
An object weighs 5.0 N in air and a spring balance reads 3.0 N when it is fully submerged in water. Taking the density of water as 1.0 × 10³ kg m⁻³ and g = 9.81 N kg⁻¹, what is its volume?
Model answer
V = upthrust/(ρg) = 2.0/(1.0 × 10³ × 9.81) = 2.0 × 10⁻⁴ m³.
- 4
The same fully submerged object is transferred from water to a denser liquid. What happens to the upthrust on it, and why?
Model answer
The upthrust increases, because the volume displaced is unchanged but the weight of that displaced volume is greater in the denser liquid.
- 5
Does the upthrust on a fully submerged object change as it is taken deeper into a liquid?
Model answer
No, because the volume of liquid displaced stays the same and the liquid's density is essentially constant with depth.
- 6
What happens to an object whose density is exactly equal to that of the surrounding fluid?
Model answer
The upthrust exactly balances its weight, so it stays in equilibrium at whatever depth it is placed.
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