Edexcel A-Level Physics 9PH0
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Electric and Magnetic Fields
Flux linkage graphs and induced e.m.f. calculations
- 2 things to know
- Papers 1 and 3
Overview
Recall questions on the gradient of a flux linkage against time graph, why its unit is the volt, electromagnetic braking, and calculating an induced e.m.f.
What you need to know
Answer each one before you reveal it.
An e.m.f. is induced in a coil whose circuit is not complete. Why does no current flow?
Questions from this subtopic
Each one with the model answer underneath.
- 1
In electromagnetic braking, what happens to the kinetic energy that is lost?
Model answer
It is transferred to internal energy, heating the metal in which the induced currents flow.
- 2
What does the gradient of a graph of flux linkage against time give?
Model answer
It gives the magnitude of the induced e.m.f.
- 3
Why is the unit of rate of change of flux linkage the volt?
Model answer
Flux linkage is measured in Wb, and 1 Wb = 1 V s, so 1 Wb s⁻¹ = 1 V.
- 4
An e.m.f. is induced in a coil whose circuit is not complete. Why does no current flow?
Model answer
An e.m.f. is still induced by the changing flux linkage, but a current can only flow if there is a complete conducting circuit.
- 5
A coil of 250 turns has the flux through it fall from 2.0 × 10⁻³ Wb to zero in 0.050 s. What is the average induced e.m.f.?
Model answer
E = NΔφ/Δt = 250 × 2.0 × 10⁻³ ÷ 0.050 = 10 V.
- 6
A 400-turn coil of area 1.5 × 10⁻³ m² has its plane at right angles to a field that falls from 0.80 T to 0.20 T in 0.30 s. What is the average induced e.m.f.?
Model answer
Δφ = ΔB × A = 0.60 × 1.5 × 10⁻³ = 9.0 × 10⁻⁴ Wb, so E = 400 × 9.0 × 10⁻⁴ ÷ 0.30 = 1.2 V.
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