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Electric and Magnetic Fields

Flux linkage graphs and induced e.m.f. calculations

  • 2 things to know
  • Papers 1 and 3

Overview

Recall questions on the gradient of a flux linkage against time graph, why its unit is the volt, electromagnetic braking, and calculating an induced e.m.f.

What you need to know

Answer each one before you reveal it.

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Numbers

What does the gradient of a flux linkage against time graph give, and what happens to the kinetic energy lost in electromagnetic braking?

Key term

An e.m.f. is induced in a coil whose circuit is not complete. Why does no current flow?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    In electromagnetic braking, what happens to the kinetic energy that is lost?

    Model answer

    It is transferred to internal energy, heating the metal in which the induced currents flow.

  2. 2

    What does the gradient of a graph of flux linkage against time give?

    Model answer

    It gives the magnitude of the induced e.m.f.

  3. 3

    Why is the unit of rate of change of flux linkage the volt?

    Model answer

    Flux linkage is measured in Wb, and 1 Wb = 1 V s, so 1 Wb s⁻¹ = 1 V.

  4. 4

    An e.m.f. is induced in a coil whose circuit is not complete. Why does no current flow?

    Model answer

    An e.m.f. is still induced by the changing flux linkage, but a current can only flow if there is a complete conducting circuit.

  5. 5

    A coil of 250 turns has the flux through it fall from 2.0 × 10⁻³ Wb to zero in 0.050 s. What is the average induced e.m.f.?

    Model answer

    E = NΔφ/Δt = 250 × 2.0 × 10⁻³ ÷ 0.050 = 10 V.

  6. 6

    A 400-turn coil of area 1.5 × 10⁻³ m² has its plane at right angles to a field that falls from 0.80 T to 0.20 T in 0.30 s. What is the average induced e.m.f.?

    Model answer

    Δφ = ΔB × A = 0.60 × 1.5 × 10⁻³ = 9.0 × 10⁻⁴ Wb, so E = 400 × 9.0 × 10⁻⁴ ÷ 0.30 = 1.2 V.

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