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Nuclear Radiation

Decay graphs and half-life calculations

  • 2 things to know
  • Papers 2 and 3

Overview

Recall questions on the exponential equations and their logarithmic form, which graph gives the decay constant, reading a half-life from a curve, and why heating changes nothing.

What you need to know

Answer each one before you reveal it.

Your recallNot started
Numbers

What is the logarithmic form of the decay equation, and why is a mean of several half-life readings better than one?

Numbers

What fraction of the original nuclei remains after 1.5 half-lives, and what happens to the half-life if the sample is heated strongly?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is the logarithmic form of N = N₀e⁻λᵗ?

    Model answer

    Taking natural logarithms gives ln N = ln N₀ − λt.

  2. 2

    What graph would you plot to obtain the decay constant from activity readings, and what would its gradient and intercept be?

    Model answer

    A graph of ln A against t gives a straight line of gradient −λ and vertical intercept ln A₀.

  3. 3

    How would you find the half-life directly from an activity–time curve?

    Model answer

    Read off the time taken for the activity to fall from any chosen value to half that value, repeat this from several different starting points and take the mean.

  4. 4

    Why is taking a mean of several half-life readings from a decay curve better than taking one?

    Model answer

    Decay is random so individual readings scatter, and averaging reduces the effect of that random variation.

  5. 5

    Why is the logarithmic graph usually the better way to obtain a half-life?

    Model answer

    It uses every data point rather than just a few, gives a straight line whose gradient can be found accurately, and makes anomalous readings easy to spot.

  6. 6

    A radioactive isotope has a half-life of 8.0 days. What is its decay constant?

    Model answer

    λ = ln 2 / (8.0 × 24 × 3600) = 0.693 / (6.91 × 10⁵) = 1.0 × 10⁻⁶ s⁻¹.

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