Edexcel A-Level Physics 9PH0
Working as a Physicist
Mechanics
Electric Circuits
Materials
Waves and Particle Nature of Light
Further Mechanics
Electric and Magnetic Fields
Nuclear and Particle Physics
Thermodynamics
Space
Nuclear Radiation
Gravitational Fields
Oscillations
Space
Luminosity, intensity and the inverse square law
- 2 things to know
- Papers 2 and 3
Overview
Recall questions on the difference between luminosity and received intensity, the equation linking them, why 4πd² appears, and the assumptions the equation makes.
What you need to know
Answer each one before you reveal it.
Why does the distance appear as 4πd² in the intensity relationship, and what happens to the intensity if the distance is trebled?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is meant by the luminosity of a star?
Model answer
It is the total radiant power the star emits in all directions, measured in watts.
- 2
What is meant by the radiation intensity received from a star?
Model answer
It is the radiant power arriving per unit area at the detector, measured in W m⁻².
- 3
State the equation relating the intensity received from a star to its luminosity and distance:
Model answer
The equation is I = L/(4πd²), where d is the distance from the source.
- 4
Why does the distance appear as 4πd² in this relationship?
Model answer
The emitted power spreads out uniformly over the surface of a sphere of radius d, and that sphere has area 4πd².
- 5
What happens to the intensity received from a star if its distance from us were three times greater?
Model answer
The intensity would fall to one ninth of its value, because intensity is inversely proportional to the square of the distance.
- 6
A star of luminosity 3.9 × 10²⁶ W is 1.5 × 10¹¹ m away. What intensity is received?
Model answer
I = 3.9 × 10²⁶/(4π × (1.5 × 10¹¹)²) = 1.4 × 10³ W m⁻².
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