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Electric Circuits

Circuit calculations, meters and component failure

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Overview

Recall questions on splitting potential difference and current between resistors, why an ammeter goes in series and a voltmeter in parallel, and what happens when a lamp fails.

What you need to know

Answer each one before you reveal it.

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Numbers

How are potential differences shared between series resistors, what happens to a parallel network when a further resistor is added, and what is the combined resistance of two identical resistors R in parallel?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    A 20 Ω resistor and a 60 Ω resistor are connected in parallel across a 12 V supply of negligible internal resistance. What is the current in each, and what is the total current?

    Model answer

    The currents are 12/20 = 0.60 A and 12/60 = 0.20 A, giving a total current of 0.80 A.

  2. 2

    How is the ratio of the potential differences across two series resistors related to their resistances?

    Model answer

    The potential differences are in the same ratio as the resistances, because the current in them is identical.

  3. 3

    How is the ratio of the currents in two parallel branches related to their resistances?

    Model answer

    The currents are in inverse ratio to the resistances, because the potential difference across the branches is identical.

  4. 4

    Why must an ammeter be connected in series, and why should its resistance be as low as possible?

    Model answer

    It must carry the current it measures, so it goes in series, and a low resistance means it adds almost nothing to the circuit resistance and so barely alters that current.

  5. 5

    Why must a voltmeter be connected in parallel, and why should its resistance be as high as possible?

    Model answer

    It measures the potential difference between two points, so it is connected across the component, and a high resistance means it draws almost no current and so barely alters the circuit.

  6. 6

    One of two lamps connected in parallel across a battery fails and goes open circuit. What happens to the current in the other lamp and to the current from the battery?

    Model answer

    The current in the remaining lamp is unchanged because the potential difference across it is the same, but the total current from the battery falls.

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