Edexcel A-Level Physics 9PH0
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Electric Circuits
The potential divider equation and the loading effect
- 3 things to know
- Papers 1 and 3
Overview
Recall questions on how potential falls along a uniform wire, the divider equation and its derivation, and why the output drops when a load is connected.
What you need to know
Answer each one before you reveal it.
What assumptions are needed for the potential to fall at a constant rate along a wire?
How is the potential divider equation derived from the circuit rules?
Questions from this subtopic
Each one with the model answer underneath.
- 1
How does the electrical potential vary with distance along a uniform wire carrying a steady current?
Model answer
It falls uniformly, so the potential difference between two points is directly proportional to the length of wire between them.
- 2
Why does the potential fall uniformly along a uniform current-carrying wire?
Model answer
The resistance of each section is proportional to its length and the current is the same throughout, so V = IR means the potential difference is proportional to length.
- 3
What assumptions are needed for the potential to fall at a constant rate along a wire?
Model answer
The wire must have a uniform cross-sectional area and uniform resistivity, which means its temperature must stay constant along its length.
- 4
A uniform wire has a potential difference of 4.0 V between its ends and is 1.0 m long. At what distance from the low-potential end is the potential 1.5 V?
Model answer
The potential is proportional to distance, so the point is at 1.5/4.0 × 1.0 = 0.375 m from that end.
- 5
What is a potential divider?
Model answer
It is two or more resistors connected in series across a supply, so that a chosen fraction of the supply potential difference appears across one of them.
- 6
State the potential divider equation for the potential difference across the second of two series resistors:
Model answer
V₂ = V × R₂/(R₁ + R₂), where V is the supply potential difference.
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