CCEA A-Level Environmental Technology 3930
Fossil Fuels
Global Action on Energy Conservation and Climate Change
Macrogeneration
Microgeneration
Energy From Wind
Energy From the Sun
Energy From Biomass
Energy Storage
Plastics for the Future
Renewable Energy Investigations
Sustainable Development
Waste Management
Waste to Energy Technologies
Land Contamination and Remediation
Hydrogen Fuel Cells
Transport System Challenges
Energy Performance of Buildings
Emerging Technologies
Sustainable Urban and Rural Communities
The Code for Sustainable Homes
Energy From Wind
Kinetic energy, wind power and the Betz limit
- 3 things to know
- AS 1
Overview
The kinetic energy of moving air, the power equation P = ½ρAv³ and why power rises with the cube of wind speed, worked rotor calculations, the Betz limit and the power coefficient of real turbines.
What you need to know
Answer each one before you reveal it.
State the equation for the kinetic energy of a moving mass of air.
Calculate the kinetic energy of 1,000 kg of air moving at 10 m/s.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation for the kinetic energy of a moving mass of air.
Model answer
Kinetic energy equals half the mass multiplied by the speed squared, Eₖ = ½mv². Energy is in joules when mass is in kilograms and speed in metres per second.
- 2
Calculate the kinetic energy of 1,000 kg of air moving at 10 m/s.
Model answer
The kinetic energy is 50,000 J, or 50 kJ. The working is ½ × 1,000 kg × (10 m/s)² = 50,000 J.
- 3
Compare the kinetic energy of 1,000 kg of air at 5 m/s with that of 1,000 kg of air at 10 m/s.
Model answer
Air of 1,000 kg moving at 5 m/s carries 12,500 J, a quarter of the 50,000 J it has at 10 m/s. Kinetic energy depends on v², so halving the speed leaves one quarter of the energy.
- 4
How much kinetic energy does one cubic metre of air moving at 8 m/s carry, taking air density as 1.2 kg/m³?
Model answer
One cubic metre of air carries about 38 J at 8 m/s. The mass is 1.2 kg, and ½ × 1.2 × 8² = 38.4 J.
- 5
Why is the power in the wind proportional to the cube of wind speed rather than the square?
Model answer
Kinetic energy per kilogram rises with v², and the mass of air passing the rotor each second also rises with v. The two effects multiply, giving power proportional to v³.
- 6
State the equation for the power available in the wind passing through a turbine rotor.
Model answer
The power available is P = ½ρAv³, where ρ is air density, A is swept area and v is wind speed. Air density is usually taken as 1.2 kg/m³.
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