CCEA A-Level Physics 1210
Physical Quantities, Scalars and Vectors
Moments and Equilibrium
Linear Motion and Dynamics
Newton's Laws of Motion
Linear Momentum and Impulse
Work, Energy and Power
Current, Charge and Potential Difference
Resistance and Resistivity
Internal Resistance and Potential Dividers
Waves
Refraction
Lenses
Superposition, Interference and Diffraction
Quantum Physics
Wave-Particle Duality
Astronomy
Practical Skills and Data Analysis
Deformation of Solids
Thermal Physics
Uniform Circular Motion
Simple Harmonic Motion
The Nucleus and Radioactive Decay
Nuclear Energy, Fission and Fusion
Gravitational Fields
Electric Fields
Capacitors
Magnetic Fields
Charged Particles and Accelerators
Astronomy
The age of the universe
- 3 things to know
- Unit AS 2
Overview
Recall questions on the estimate t ≈ 1/H₀ and how it follows from Hubble's law, worked calculations in seconds and in years, the assumption of a constant expansion rate and why it is not exactly right, the effect of a larger Hubble constant, why the oldest stars must be younger than the estimate, and the observable limit a finite age imposes.
What you need to know
Answer each one before you reveal it.
How does the finite age of the universe limit how much of it can be observed?
How would evidence that the expansion of the universe is speeding up affect the estimate of its age?
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the relation used to estimate the age of the universe from the Hubble constant, defining each symbol.
Model answer
t ≈ 1/H₀, where t is the estimated age of the universe in seconds and H₀ is the Hubble constant in s⁻¹.
- 2
Show how the age relation follows from Hubble's law.
Model answer
If a galaxy has been receding at a constant speed v ever since the expansion began, then d = vt, so t = d/v, and substituting v = H₀d gives t = d/(H₀d) = 1/H₀.
- 3
Calculate the age of the universe in seconds, taking the Hubble constant as 2.4 × 10⁻¹⁸ s⁻¹.
Model answer
t = 1/H₀ = 1/2.4 × 10⁻¹⁸ = 4.2 × 10¹⁷ s, and 1 ÷ 4.17 × 10¹⁷ s returns 2.4 × 10⁻¹⁸ s⁻¹ as given.
- 4
Convert an age of 4.2 × 10¹⁷ s into years, taking one year as 3.15 × 10⁷ s.
Model answer
t = 4.17 × 10¹⁷ / 3.15 × 10⁷ = 1.3 × 10¹⁰ years, that is about 13 billion years, and 1.32 × 10¹⁰ × 3.15 × 10⁷ returns 4.2 × 10¹⁷ s.
- 5
What assumption about the expansion is made when the age of the universe is estimated as 1/H₀?
Model answer
It assumes every galaxy has been receding at the same constant speed since the expansion began, so that the rate of expansion has never changed.
- 6
Why is the assumption behind the 1/H₀ estimate not exactly correct?
Model answer
Gravity between all the matter in the universe has acted to slow the expansion, and observations indicate the expansion rate has also changed in other ways, so the rate now is not the rate it has always had.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Astronomy, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
Or £46 a year, about £3.83 a month. Cancel anytime.