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Capacitors

Flash guns and defibrillators

  • 3 things to know
  • Unit A2 2

Overview

Two very different time constants involved in a flash gun and general principle these applications share.

What you need to know

Answer each one before you reveal it.

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Key term

Explain the two very different time constants involved in a flash gun.

Key term

Why is there a delay before a flash gun can be used again?

Numbers

A flash gun releases 67.5 J of stored energy in 2.0 ms. Calculate the average power

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Why is a capacitor used in an electronic flash gun?

    Model answer

    It stores energy slowly from a small battery and then releases it all in a few milliseconds, giving a burst of power far greater than the battery could supply.

  2. 2

    Explain the two very different time constants involved in a flash gun.

    Model answer

    Charging is through a large resistance so the time constant is seconds, while discharge is through the very low resistance of the flash tube so the time constant is milliseconds.

  3. 3

    Why is there a delay before a flash gun can be used again?

    Model answer

    The capacitor has to recharge through the large charging resistance, which takes several seconds.

  4. 4

    A flash gun capacitor of 1500 μF is charged to 300 V. Calculate the energy stored.

    Model answer

    E = 0.5 × 1500 × 10⁻⁶ × 300², which is 0.5 × 1500 × 10⁻⁶ × 9.0 × 10⁴, giving 67.5 J.

  5. 5

    Calculate the average power if that energy is released in 2.0 ms.

    Model answer

    P = E/t = 67.5 ÷ 2.0 × 10⁻³, which is 3.4 × 10⁴ W.

  6. 6

    What does a defibrillator do?

    Model answer

    It passes a controlled pulse of charge through the heart to stop a chaotic rhythm, allowing the heart's own pacemaker to restart a normal beat.

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