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Capacitors

Energy stored in a charged capacitor

  • 3 things to know
  • Unit A2 2

Overview

Recall questions on E = ½QV and its two equivalent forms, why the factor of ½ appears, the energy as the area under a charge against potential difference graph, the fourfold rise when the voltage doubles, worked energy calculations, why only half the battery's energy is stored, and the defibrillator as a worked case.

What you need to know

Answer each one before you reveal it.

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Key term

Give the equation for the energy stored in a charged capacitor in terms of charge and potential difference.

Key term

Why is the energy stored ½QV rather than QV?

Key term

A 100 μF capacitor charged to 50 V stores 0.125 J by ½CV². Check that energy using the charge stored

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Give the equation for the energy stored in a charged capacitor in terms of charge and potential difference.

    Model answer

    E = ½QV, where E is the energy in joules, Q the charge in coulombs and V the potential difference in volts.

  2. 2

    Why is the energy stored ½QV rather than QV?

    Model answer

    The potential difference rises from zero to V as the capacitor charges, so the average potential difference during charging is only half the final value.

  3. 3

    How is the energy stored found from a graph of charge against potential difference?

    Model answer

    It is the area under the line, which for a straight line through the origin is the area of a triangle, ½QV.

  4. 4

    Calculate the energy stored by a 100 μF capacitor charged to 50 V.

    Model answer

    E = ½CV² = 0.5 × 100 × 10⁻⁶ × 50², which is 0.5 × 100 × 10⁻⁶ × 2500, giving 0.125 J.

  5. 5

    Check that energy using the charge stored.

    Model answer

    Q = CV = 100 × 10⁻⁶ × 50 = 5.0 × 10⁻³ C, and ½QV = 0.5 × 5.0 × 10⁻³ × 50 = 0.125 J, which agrees.

  6. 6

    The potential difference across a capacitor is doubled. What happens to the energy stored?

    Model answer

    It becomes four times as great, because energy is proportional to the square of the potential difference.

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