CCEA A-Level Physics 1210
Physical Quantities, Scalars and Vectors
Moments and Equilibrium
Linear Motion and Dynamics
Newton's Laws of Motion
Linear Momentum and Impulse
Work, Energy and Power
Current, Charge and Potential Difference
Resistance and Resistivity
Internal Resistance and Potential Dividers
Waves
Refraction
Lenses
Superposition, Interference and Diffraction
Quantum Physics
Wave-Particle Duality
Astronomy
Practical Skills and Data Analysis
Deformation of Solids
Thermal Physics
Uniform Circular Motion
Simple Harmonic Motion
The Nucleus and Radioactive Decay
Nuclear Energy, Fission and Fusion
Gravitational Fields
Electric Fields
Capacitors
Magnetic Fields
Charged Particles and Accelerators
Nuclear Energy, Fission and Fusion
Mass–energy equivalence and E = Δmc²
- 3 things to know
- Unit A2 1
Overview
What is meant by the equivalence of mass and energy, equation linking a change in mass to the energy released and value of the electronvolt in joules.
What you need to know
Answer each one before you reveal it.
State the equation linking a change in mass to the energy released, and define every symbol.
State the value of the speed of light in a vacuum and the value of c².
Questions from this subtopic
Each one with the model answer underneath.
- 1
State what is meant by the equivalence of mass and energy.
Model answer
Mass and energy are two forms of the same thing, so any change in the energy of a system is accompanied by a proportional change in its mass, and mass can be converted into energy and energy into mass.
- 2
State the equation linking a change in mass to the energy released, and define every symbol.
Model answer
E = Δmc², where E is the energy in joules, Δm the change in mass in kilograms and c the speed of light in a vacuum, 3.00 × 10⁸ m s⁻¹.
- 3
State the value of the speed of light in a vacuum and the value of c².
Model answer
The speed of light in a vacuum is c = 3.00 × 10⁸ m s⁻¹, so c² = 9.00 × 10¹⁶ m² s⁻².
- 4
Why is only a very small mass needed to release a very large amount of energy?
Model answer
The conversion factor c² is 9.00 × 10¹⁶ m² s⁻², so even a mass of a milligram corresponds to an energy of about 10¹¹ J.
- 5
Calculate the energy released when a mass of 1.0 × 10⁻³ kg is completely converted into energy.
Model answer
E = Δmc² = 1.0 × 10⁻³ × 9.00 × 10¹⁶ = 9.0 × 10¹³ J.
- 6
Calculate the energy equivalent of one unified atomic mass unit in joules.
Model answer
E = Δmc² = 1.66 × 10⁻²⁷ × 9.00 × 10¹⁶ = 1.49 × 10⁻¹⁰ J.
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