CCEA A-Level Physics 1210
Physical Quantities, Scalars and Vectors
Moments and Equilibrium
Linear Motion and Dynamics
Newton's Laws of Motion
Linear Momentum and Impulse
Work, Energy and Power
Current, Charge and Potential Difference
Resistance and Resistivity
Internal Resistance and Potential Dividers
Waves
Refraction
Lenses
Superposition, Interference and Diffraction
Quantum Physics
Wave-Particle Duality
Astronomy
Practical Skills and Data Analysis
Deformation of Solids
Thermal Physics
Uniform Circular Motion
Simple Harmonic Motion
The Nucleus and Radioactive Decay
Nuclear Energy, Fission and Fusion
Gravitational Fields
Electric Fields
Capacitors
Magnetic Fields
Charged Particles and Accelerators
Resistance and Resistivity
Electrical power and energy in resistive circuits
- 3 things to know
- Unit AS 1
Overview
Recall questions on P = VI and the derivations of P = I²R and P = V²/R, the factor of four when current doubles, calculating energy transferred over a time, why transmission is at high voltage, which of two resistors dissipates more in series and in parallel, and why a fuse melts.
What you need to know
Answer each one before you reveal it.
State the equation for the power dissipated in a resistor in terms of potential difference and resistance.
A current of 3.0 A flows through an 8.0 Ω resistor for 2.0 minutes. Calculate the energy dissipated.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the equation for the power dissipated in a resistor in terms of current and resistance, and define every symbol.
Model answer
The equation is P = I²R, where P is the power in watts, I the current in amperes and R the resistance in ohms.
- 2
Show how P = I²R follows from P = VI.
Model answer
For a resistor V = IR, so substituting into P = VI gives P = (IR)I = I²R.
- 3
State the equation for the power dissipated in a resistor in terms of potential difference and resistance.
Model answer
The power is P = V²/R, obtained by substituting I = V/R into P = VI, where V is in volts and R in ohms.
- 4
Calculate the power dissipated when a current of 2.0 A flows through a 15 Ω resistor.
Model answer
The power is P = I²R = 2.0² × 15 = 60 W, and 60 W ÷ 2.0 A gives 30 V, which is indeed 2.0 A × 15 Ω, confirming the result.
- 5
Calculate the power dissipated in a 6.0 Ω resistor with a potential difference of 12 V across it.
Model answer
The power is P = V²/R = 144 ÷ 6.0 = 24 W, and the current is 2.0 A so P = VI = 12 × 2.0 = 24 W, confirming the result.
- 6
A heater is rated at 1.2 kW when connected to a 230 V supply. Calculate the resistance of its element.
Model answer
The resistance is R = V²/P = 52 900 ÷ 1200 = 44 Ω, and 230² ÷ 44.1 returns 1.2 × 10³ W as a check.
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