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Lenses

The power of a lens

  • 3 things to know
  • Unit AS 2

Overview

Recall questions on the definition of lens power and the equation P = 1/f with the dioptre, the signs for a converging and a diverging lens, worked conversions both ways, combining two thin lenses in contact, why opticians specify power rather than focal length, and what a negative prescription indicates.

What you need to know

Answer each one before you reveal it.

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Numbers

A lens of power +3.0 D is placed in contact with one of power −1.0 D. Calculate the power and focal length of the combination.

Key term

Why do opticians specify lenses by power rather than by focal length?

Numbers

Calculate the focal length of a lens of power +50 D and comment on the result.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Define the power of a lens.

    Model answer

    The power of a lens is the reciprocal of its focal length, and it is a measure of how strongly the lens converges or diverges light.

  2. 2

    State the equation for the power of a lens, defining each symbol and giving the unit.

    Model answer

    P = 1/f, where P is the power in dioptres (D) and f is the focal length in metres, so one dioptre is one m⁻¹.

  3. 3

    What sign does the power of a converging lens have, and what sign does a diverging lens have?

    Model answer

    A converging lens has a positive power and a diverging lens a negative power, following the sign of the focal length.

  4. 4

    Calculate the power of a converging lens of focal length 0.25 m.

    Model answer

    P = 1/f = 1/0.25 = +4.0 D, and 1/4.0 D returns a focal length of 0.25 m as given.

  5. 5

    A lens has a power of −2.5 D. Calculate its focal length and state the type of lens.

    Model answer

    f = 1/P = 1/(−2.5) = −0.40 m, so it is a diverging lens of focal length 0.40 m, and 1/(−0.40 m) returns −2.5 D.

  6. 6

    Which lens bends light more strongly, one of power +2.0 D or one of power +5.0 D?

    Model answer

    The +5.0 D lens, because a higher power means a shorter focal length, 0.20 m rather than 0.50 m, and therefore a greater deviation of the light.

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