CCEA A-Level Physics 1210
Physical Quantities, Scalars and Vectors
Moments and Equilibrium
Linear Motion and Dynamics
Newton's Laws of Motion
Linear Momentum and Impulse
Work, Energy and Power
Current, Charge and Potential Difference
Resistance and Resistivity
Internal Resistance and Potential Dividers
Waves
Refraction
Lenses
Superposition, Interference and Diffraction
Quantum Physics
Wave-Particle Duality
Astronomy
Practical Skills and Data Analysis
Deformation of Solids
Thermal Physics
Uniform Circular Motion
Simple Harmonic Motion
The Nucleus and Radioactive Decay
Nuclear Energy, Fission and Fusion
Gravitational Fields
Electric Fields
Capacitors
Magnetic Fields
Charged Particles and Accelerators
Lenses
The power of a lens
- 3 things to know
- Unit AS 2
Overview
Recall questions on the definition of lens power and the equation P = 1/f with the dioptre, the signs for a converging and a diverging lens, worked conversions both ways, combining two thin lenses in contact, why opticians specify power rather than focal length, and what a negative prescription indicates.
What you need to know
Answer each one before you reveal it.
Why do opticians specify lenses by power rather than by focal length?
Calculate the focal length of a lens of power +50 D and comment on the result.
Questions from this subtopic
Each one with the model answer underneath.
- 1
Define the power of a lens.
Model answer
The power of a lens is the reciprocal of its focal length, and it is a measure of how strongly the lens converges or diverges light.
- 2
State the equation for the power of a lens, defining each symbol and giving the unit.
Model answer
P = 1/f, where P is the power in dioptres (D) and f is the focal length in metres, so one dioptre is one m⁻¹.
- 3
What sign does the power of a converging lens have, and what sign does a diverging lens have?
Model answer
A converging lens has a positive power and a diverging lens a negative power, following the sign of the focal length.
- 4
Calculate the power of a converging lens of focal length 0.25 m.
Model answer
P = 1/f = 1/0.25 = +4.0 D, and 1/4.0 D returns a focal length of 0.25 m as given.
- 5
A lens has a power of −2.5 D. Calculate its focal length and state the type of lens.
Model answer
f = 1/P = 1/(−2.5) = −0.40 m, so it is a diverging lens of focal length 0.40 m, and 1/(−0.40 m) returns −2.5 D.
- 6
Which lens bends light more strongly, one of power +2.0 D or one of power +5.0 D?
Model answer
The +5.0 D lens, because a higher power means a shorter focal length, 0.20 m rather than 0.50 m, and therefore a greater deviation of the light.
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