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Gravitational Fields

Circular motion of planets and satellites

  • 3 things to know
  • Unit A2 2

Overview

Recall questions on what supplies the centripetal force in orbit, setting the gravitational force equal to mv²/r and deriving v = √(GM/r), why the satellite's own mass cancels, how speed varies with orbital radius, worked speed and period calculations, why the gravitational force does no work, and why a low orbit decays.

What you need to know

Answer each one before you reveal it.

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Key term

Write the equation obtained by setting the gravitational force equal to the centripetal force for a circular orbit.

Key term

What provides the centripetal force that keeps a satellite in orbit?

Key term

Rearrange GMm/r² = mv²/r to give the orbital speed of a satellite, and define each symbol

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What provides the centripetal force that keeps a satellite in orbit?

    Model answer

    The gravitational attraction between the satellite and the body it orbits.

  2. 2

    Write the equation obtained by setting the gravitational force equal to the centripetal force for a circular orbit.

    Model answer

    GMm/r² = mv²/r, where M is the mass of the central body, m the mass of the orbiting body, v its orbital speed and r the orbital radius.

  3. 3

    Rearrange that to give the orbital speed, and define each symbol.

    Model answer

    Cancelling m and one factor of r gives v = √(GM/r), where v is the orbital speed in m s⁻¹, G the gravitational constant, M the central mass in kilograms and r the orbital radius in metres.

  4. 4

    Why does the mass of the satellite not affect its orbital speed?

    Model answer

    The satellite's mass appears on both sides of the equation and cancels, so at a given radius every satellite must travel at the same speed.

  5. 5

    How does orbital speed change with orbital radius?

    Model answer

    Speed falls as radius increases, in proportion to one over the square root of the radius, so a distant satellite moves more slowly than a near one.

  6. 6

    Calculate the orbital speed of a satellite at a radius of 7.0 × 10⁶ m around the Earth, taking M as 6.0 × 10²⁴ kg.

    Model answer

    v = √(6.67 × 10⁻¹¹ × 6.0 × 10²⁴ ÷ 7.0 × 10⁶) = √(5.72 × 10⁷), which is 7.6 × 10³ m s⁻¹.

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