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Deformation of Solids

Measuring the Young modulus of a wire

  • 3 things to know
  • Unit A2 1

Overview

Recall questions on the apparatus and why the wire is long and thin, measuring the diameter with a micrometer in several places and two directions, finding the area, what is plotted and what the gradient gives, the purpose of the comparison wire, the tensioning load, checking the elastic limit has not been passed, and the safety precautions.

What you need to know

Answer each one before you reveal it.

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Key term

Describe the apparatus used to measure the Young modulus of a metal in the form of a long thin wire.

Key term

When measuring the Young modulus, why is the test wire made as long and as thin as is practical?

Key term

In a Young modulus experiment, which instrument is used to measure the diameter of the wire, and what is its precision?

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    Describe the apparatus used to measure the Young modulus of a metal in the form of a long thin wire.

    Model answer

    A long wire is clamped firmly at one end, run over a pulley at the edge of a bench or hung vertically from a ceiling clamp, and loaded with slotted masses at the free end. A marker taped to the wire is read against a millimetre scale fixed alongside it.

  2. 2

    Why is the test wire made as long and as thin as is practical?

    Model answer

    A long thin wire gives the largest extension for a given load, so the extension is measured with a much smaller percentage uncertainty.

  3. 3

    Which instrument is used to measure the diameter of the wire, and what is its precision?

    Model answer

    A micrometer screw gauge is used, reading to 0.01 mm.

  4. 4

    Why is the diameter of the wire measured at several places along it and in two directions at each place?

    Model answer

    The wire may not be perfectly uniform along its length or perfectly circular in section, so a mean diameter gives a more reliable cross-sectional area.

  5. 5

    How is the cross-sectional area of the wire found from its diameter?

    Model answer

    A = πd²/4, where d is the mean diameter in metres and A the area in m².

  6. 6

    Why is the diameter of the wire usually the largest source of uncertainty in this experiment?

    Model answer

    The diameter is a very small quantity to measure and it is squared when the area is calculated, so its percentage uncertainty is doubled in the final value of E.

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