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Refraction

Snell's law

  • 3 things to know
  • Unit AS 2

Overview

Recall questions on the statement of Snell's law and its air-to-medium form, the definition of the angle of incidence and why angles are measured from the normal, worked calculations across air-to-glass and water-to-glass boundaries, the law written in terms of speeds and of wavelengths, and the graph of sin i against sin r.

What you need to know

Answer each one before you reveal it.

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Numbers

Light strikes a glass block of refractive index 1.50 at an angle of incidence of 30°. Calculate the angle of refraction.

Numbers

A ray inside glass of refractive index 1.50 meets the surface at 20° to the normal and emerges into air. Calculate the angle in air.

Key term

State Snell's law in the simpler form used when light travels from air into a material.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State Snell's law for a ray crossing a boundary between two media, defining each symbol.

    Model answer

    n₁ sin θ₁ = n₂ sin θ₂, where n₁ and n₂ are the refractive indices of the first and second media and θ₁ and θ₂ are the angles between the ray and the normal in each medium.

  2. 2

    State Snell's law in the simpler form used when light travels from air into a material.

    Model answer

    n = sin i / sin r, where n is the refractive index of the material, i is the angle of incidence in air and r is the angle of refraction in the material, both measured from the normal.

  3. 3

    Define the angle of incidence.

    Model answer

    The angle of incidence is the angle between the incident ray and the normal to the surface at the point where the ray strikes it.

  4. 4

    Why are the angles in Snell's law measured from the normal rather than from the surface?

    Model answer

    The normal gives a single well-defined reference line at any point on a surface, including a curved one, and it keeps the law in the same form for every shape of boundary.

  5. 5

    Light strikes a glass block of refractive index 1.50 at an angle of incidence of 30°. Calculate the angle of refraction.

    Model answer

    sin r = sin 30° / 1.50 = 0.500/1.50 = 0.333, so r = 19.5°, and 1.50 × sin 19.5° = 0.500 = sin 30° as given.

  6. 6

    A ray inside glass of refractive index 1.50 meets the surface at 20° to the normal and emerges into air. Calculate the angle in air.

    Model answer

    sin θₐᵢᵣ = 1.50 × sin 20° = 1.50 × 0.342 = 0.513, so θₐᵢᵣ = 30.9°, and sin 30.9° ÷ 1.50 returns sin 20° as given.

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