CCEA A-Level Physics 1210
Physical Quantities, Scalars and Vectors
Moments and Equilibrium
Linear Motion and Dynamics
Newton's Laws of Motion
Linear Momentum and Impulse
Work, Energy and Power
Current, Charge and Potential Difference
Resistance and Resistivity
Internal Resistance and Potential Dividers
Waves
Refraction
Lenses
Superposition, Interference and Diffraction
Quantum Physics
Wave-Particle Duality
Astronomy
Practical Skills and Data Analysis
Deformation of Solids
Thermal Physics
Uniform Circular Motion
Simple Harmonic Motion
The Nucleus and Radioactive Decay
Nuclear Energy, Fission and Fusion
Gravitational Fields
Electric Fields
Capacitors
Magnetic Fields
Charged Particles and Accelerators
Internal Resistance and Potential Dividers
Loaded potential dividers and output voltage calculations
- 3 things to know
- Unit AS 1
Overview
Recall questions on what loading means and why it lowers the output, the procedure of combining the load in parallel with the lower arm first, worked calculations for several load resistances, the condition for the loading effect to be negligible, why low-value resistors reduce it and what that costs, and the loading effect of a voltmeter.
What you need to know
Answer each one before you reveal it.
Why is a plain potential divider unsuitable for supplying a load whose resistance changes while it is operating?
Why does connecting a load across the output of a potential divider reduce the output potential difference?
Questions from this subtopic
Each one with the model answer underneath.
- 1
What is meant by a loaded potential divider?
Model answer
A loaded potential divider is one that has a further component or circuit connected across its output, so that the output has to supply current to that load as well as to the divider chain.
- 2
Why does connecting a load across the output of a potential divider reduce the output potential difference?
Model answer
The load is in parallel with the lower arm of the divider, which reduces the resistance of that arm, so a smaller fraction of the supply potential difference now appears across it.
- 3
Describe the procedure for calculating the output of a loaded potential divider.
Model answer
First combine the load resistance in parallel with the resistance of the arm across which the output is taken, then apply the potential divider equation using that combined value in place of the original arm resistance.
- 4
A 12 V supply feeds a divider of two 6.0 kΩ resistors and a 6.0 kΩ load is connected across the output. Calculate the loaded output potential difference.
Model answer
The lower arm becomes 6.0 kΩ in parallel with 6.0 kΩ, which is 3.0 kΩ, so the output is 12 × 3.0 ÷ (6.0 + 3.0) = 4.0 V, compared with 6.0 V unloaded.
- 5
A 9.0 V supply feeds a divider with a 1.0 kΩ upper arm and a 2.0 kΩ lower arm, and a 2.0 kΩ load is connected across the output. Calculate the loaded output and compare it with the unloaded value.
Model answer
The lower arm becomes 2.0 kΩ in parallel with 2.0 kΩ, which is 1.0 kΩ, so the output is 9.0 × 1.0 ÷ 2.0 = 4.5 V, whereas unloaded it would have been 9.0 × 2.0 ÷ 3.0 = 6.0 V.
- 6
What condition must the load satisfy if the loading effect on a potential divider is to be negligible?
Model answer
The load resistance must be much larger than the resistance of the arm it is connected across, in practice at least about ten times as large, so that the parallel combination is close to the arm's own value.
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