CCEA A-Level Physics 1210
Physical Quantities, Scalars and Vectors
Moments and Equilibrium
Linear Motion and Dynamics
Newton's Laws of Motion
Linear Momentum and Impulse
Work, Energy and Power
Current, Charge and Potential Difference
Resistance and Resistivity
Internal Resistance and Potential Dividers
Waves
Refraction
Lenses
Superposition, Interference and Diffraction
Quantum Physics
Wave-Particle Duality
Astronomy
Practical Skills and Data Analysis
Deformation of Solids
Thermal Physics
Uniform Circular Motion
Simple Harmonic Motion
The Nucleus and Radioactive Decay
Nuclear Energy, Fission and Fusion
Gravitational Fields
Electric Fields
Capacitors
Magnetic Fields
Charged Particles and Accelerators
Moments and Equilibrium
The principle of moments
- 3 things to know
- Unit AS 1
Overview
Recall questions on the statement of the principle, the two conditions for a rigid body in equilibrium, choosing the point to take moments about so an unknown reaction drops out, and worked problems on a seesaw, a plank on two supports, a hinged beam and a wheelbarrow.
What you need to know
Answer each one before you reveal it.
Explain why the clockwise and anticlockwise moments in the principle of moments must be taken about the same point.
Explain why a body can have zero resultant force acting on it and still not be in equilibrium.
Questions from this subtopic
Each one with the model answer underneath.
- 1
State the principle of moments.
Model answer
For a body in equilibrium, the sum of the clockwise moments about any point equals the sum of the anticlockwise moments about that same point.
- 2
State the two conditions that must both be satisfied for a rigid body acted on by coplanar forces to be in equilibrium.
Model answer
The resultant force on the body must be zero, and the resultant moment about any point must also be zero.
- 3
Explain why the clockwise and anticlockwise moments in the principle of moments must be taken about the same point.
Model answer
The lever arm of every force depends on which point is chosen, so moments taken about different points measure different turning effects and cannot be set equal to one another.
- 4
When a moments problem contains an unknown reaction force, why is it convenient to take moments about the point where that force acts?
Model answer
The perpendicular distance to that force is then zero, so its moment vanishes from the equation and the remaining unknown can be found directly.
- 5
Explain why a body can have zero resultant force acting on it and still not be in equilibrium.
Model answer
Two equal and opposite forces acting along different lines give no resultant force but do give a resultant moment, so the body rotates even though it does not accelerate along a line.
- 6
A light beam is pivoted at its centre. A force of 12 N acts downwards 0.30 m to the left of the pivot. Calculate the downward force needed 0.20 m to the right to balance it.
Model answer
The anticlockwise moment is 12 × 0.30 = 3.6 N m, so the balancing force is F = 3.6 ÷ 0.20 = 18 N; checking back, 18 × 0.20 = 3.6 N m, which matches the moment on the other side.
Other ways to work this
The same content, four other ways.
What is inside Levo
Six ways to work the same material.
Every question in Moments and Equilibrium, on a schedule.
Attempt a question from memory, write the correct version, then attempt it again. Levo records the jump between your first attempt and your last, and brings each question back on the day you are due to forget it.
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