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Moments and Equilibrium

The principle of moments

  • 3 things to know
  • Unit AS 1

Overview

Recall questions on the statement of the principle, the two conditions for a rigid body in equilibrium, choosing the point to take moments about so an unknown reaction drops out, and worked problems on a seesaw, a plank on two supports, a hinged beam and a wheelbarrow.

What you need to know

Answer each one before you reveal it.

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Key term

State the two conditions that must both be satisfied for a rigid body acted on by coplanar forces to be in equilibrium.

Key term

Explain why the clockwise and anticlockwise moments in the principle of moments must be taken about the same point.

Key term

Explain why a body can have zero resultant force acting on it and still not be in equilibrium.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    State the principle of moments.

    Model answer

    For a body in equilibrium, the sum of the clockwise moments about any point equals the sum of the anticlockwise moments about that same point.

  2. 2

    State the two conditions that must both be satisfied for a rigid body acted on by coplanar forces to be in equilibrium.

    Model answer

    The resultant force on the body must be zero, and the resultant moment about any point must also be zero.

  3. 3

    Explain why the clockwise and anticlockwise moments in the principle of moments must be taken about the same point.

    Model answer

    The lever arm of every force depends on which point is chosen, so moments taken about different points measure different turning effects and cannot be set equal to one another.

  4. 4

    When a moments problem contains an unknown reaction force, why is it convenient to take moments about the point where that force acts?

    Model answer

    The perpendicular distance to that force is then zero, so its moment vanishes from the equation and the remaining unknown can be found directly.

  5. 5

    Explain why a body can have zero resultant force acting on it and still not be in equilibrium.

    Model answer

    Two equal and opposite forces acting along different lines give no resultant force but do give a resultant moment, so the body rotates even though it does not accelerate along a line.

  6. 6

    A light beam is pivoted at its centre. A force of 12 N acts downwards 0.30 m to the left of the pivot. Calculate the downward force needed 0.20 m to the right to balance it.

    Model answer

    The anticlockwise moment is 12 × 0.30 = 3.6 N m, so the balancing force is F = 3.6 ÷ 0.20 = 18 N; checking back, 18 × 0.20 = 3.6 N m, which matches the moment on the other side.

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