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Principles of Research and Application of Research Methods
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Applied Research Methods
Applied Research Methods
Inferential Statistics: calculating test values and choosing a significance level
- 2 things to know
- A2 Unit 4
Overview
Worked chi-squared, sign test, Wilcoxon, Mann Whitney and Spearman calculations compared with critical values, what p = 0.05 means, and when to use p ≤ 0.01 or a one-tailed value.
What you need to know
Answer each one before you reveal it.
Ten pairs of ranks give Σd² = 44. Calculate Spearman's rho.
Questions from this subtopic
Each one with the model answer underneath.
- 1
The critical value of chi-squared at p ≤ 0.05 with 1 degree of freedom is 3.84. What should be concluded from the calculated value of 4.29?
Model answer
The result is significant, because chi-squared must equal or exceed its critical value and 4.29 is greater than 3.84, so the null hypothesis is rejected at the 0.05 level.
- 2
Fifteen participants are tested before and after a relaxation session: eleven improved, two got worse and two showed no change. State N and the observed value of S for a sign test.
Model answer
N is 13, because the two participants who showed no change are discarded, and S is 2, the count of the less frequent sign.
- 3
The critical value of S for N = 13 at p ≤ 0.05 for a one-tailed test is 3. What should be concluded from an observed S of 2?
Model answer
The result is significant, because for the sign test the observed value must be equal to or less than the critical value, and 2 is less than 3, so the null hypothesis is rejected.
- 4
Describe how the observed value of T is obtained in a Wilcoxon matched pairs signed ranks test.
Model answer
Find the difference for each pair of scores, discard any difference of zero, rank the remaining differences by size while ignoring their signs, giving tied differences the mean of the ranks they would have occupied, then add up the ranks belonging to the less frequent sign to give T.
- 5
Eight pairs of scores give differences of +5, +3, −2, +7, +1, +4, +6 and +8. State N and the value of T.
Model answer
N is 8 and T is 2, because only the difference of −2 carries the less frequent sign and, being the second smallest difference in size, it takes rank 2.
- 6
In a Mann Whitney U test with five participants in each group, the ranks of the first group total 39 and those of the second total 16. Calculate the observed value of U.
Model answer
U = 1, because U = n₁n₂ + n₁(n₁ + 1) ÷ 2 − R gives 25 + 15 − 39 = 1 for the first group and 25 + 15 − 16 = 24 for the second, and the smaller of the two is taken.
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