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Medical Physics

Ultrasound A-scans, B-scans and acoustic impedance

  • 3 things to know
  • A2 3

Overview

Ultrasound frequencies and probes, specific acoustic impedance and the intensity reflection coefficient with worked values, coupling gel, A-scans and B-scans, echo depth, frequency choice and wavelength.

What you need to know

Answer each one before you reveal it.

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Key term

What is ultrasound, and what frequencies are used in medical imaging?

Key term

How is ultrasound produced and detected in a probe?

Key term

Define specific acoustic impedance.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is ultrasound, and what frequencies are used in medical imaging?

    Model answer

    Ultrasound is sound with a frequency above 20 kHz, beyond the range of human hearing. Medical imaging typically uses frequencies from 1 MHz to 18 MHz.

  2. 2

    How is ultrasound produced and detected in a probe?

    Model answer

    A piezoelectric crystal vibrates when an alternating voltage is applied, producing ultrasound. Echoes reaching the probe make the same crystal vibrate and generate a voltage, so the crystal also detects them.

  3. 3

    Define specific acoustic impedance.

    Model answer

    Specific acoustic impedance Z is the density of a material multiplied by the speed of sound in it. The unit of Z is kg m⁻² s⁻¹.

  4. 4

    Soft tissue has a density of 1060 kg m⁻³ and a speed of sound of 1540 m s⁻¹. Calculate its acoustic impedance.

    Model answer

    The acoustic impedance is about 1.63 × 10⁶ kg m⁻² s⁻¹. The working is Z = ρc = 1060 × 1540 = 1.63 × 10⁶ kg m⁻² s⁻¹.

  5. 5

    What is the intensity reflection coefficient, and how is it calculated?

    Model answer

    The intensity reflection coefficient R is the fraction of the incident ultrasound intensity reflected at a boundary. The equation is R = (Z₂ − Z₁)² ÷ (Z₂ + Z₁)².

  6. 6

    Fat has Z = 1.38 × 10⁶ kg m⁻² s⁻¹ and muscle has Z = 1.70 × 10⁶ kg m⁻² s⁻¹. Calculate R at a fat–muscle boundary.

    Model answer

    The reflection coefficient is about 0.011, so about 1.1% of the intensity is reflected. The working is R = (1.70 − 1.38)² ÷ (1.70 + 1.38)² = 0.32² ÷ 3.08² = 0.011.

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