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Electronic Control Systems

Potential dividers, sensors and comparators

  • 3 things to know
  • AS 1 Paper 2

Overview

The potential divider equation with worked outputs, LDRs and thermistors in dark, light and frost sensors, variable resistors, and comparators with reference voltages.

What you need to know

Answer each one before you reveal it.

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Key term

What is a potential divider?

Key term

State the potential divider equation.

Numbers

Calculate Vₒᵤₜ for a 9 V supply with R₁ = 10 kΩ and R₂ = 5 kΩ.

Questions from this subtopic

Each one with the model answer underneath.

  1. 1

    What is a potential divider?

    Model answer

    A potential divider is two resistances in series across a supply. The output voltage is taken from the junction between them.

  2. 2

    State the potential divider equation.

    Model answer

    Vₒᵤₜ = Vᵢₙ × R₂ ÷ (R₁ + R₂). R₂ is the resistor across which the output is taken.

  3. 3

    Calculate Vₒᵤₜ for a 9 V supply with R₁ = 10 kΩ and R₂ = 5 kΩ.

    Model answer

    The output voltage is 3 V. Vₒᵤₜ = 9 × 5 ÷ (10 + 5) = 3 V.

  4. 4

    How does the resistance of an LDR change with light level?

    Model answer

    An LDR's resistance falls as the light level rises. The resistance is very high in darkness and low in bright light.

  5. 5

    An LDR sits beneath a 10 kΩ resistor on a 6 V supply, with the output taken across the LDR. Calculate Vₒᵤₜ when the LDR is 100 kΩ in darkness.

    Model answer

    The output rises to about 5.5 V in darkness. Vₒᵤₜ = 6 × 100 ÷ (10 + 100) = 5.45 V.

  6. 6

    Explain why an LDR in the lower position of a divider gives a dark-activated sensor.

    Model answer

    Darkness raises the LDR's resistance, so the LDR takes a larger share of the supply voltage. The output across the LDR therefore rises as the light falls.

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The output voltage is V.
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AThe total resistance is 2 kΩ.
BThe parallel pair gives (2 × 2) ÷ (2 + 2) = 1 kΩ.
CThe series resistor adds another 1 kΩ.

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